Q: What is the factorization of this trinomial -3x2 10x-8?

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It is: (-3x-4)(x+2) when factored

(3x + 1)(x - 4)

(3x+1)(x+2)

(x + 5)(x - 8)

x(x - 4)(x - 6)

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3x2 + 36x + 81 = 3(x2 + 13x + 27)

3x^2 + 10x + 8 = (3x + 4)(x + 2)

-(3x+4)(x+2)

It is: (-3x-4)(x+2) when factored

Do you mean 3x2+10x-8 if so then it is (3x-2(x+4) when factored

[ x3 + 3x2 + 2x ] is a trinomial. It's factors are [ x, (x + 1), (x + 2) ] .

3x2 + 36x + 81 = 3(x2 + 12x + 27) = 3(x + 3)(x + 9), which are its prime factors; or, if you prefer, 3x2 + 36x + 81 = (3x + 9)(x + 9), which is also accurate. You may easily verify these results by multiplying back.

3x2+7-6 = (3x-2)(x+3) when factored

3x2-7x+4 = (3x-4)(x-1) when factored

(3x + 1)(x - 4)

-3x2+10x-3 -(3x2-10x+3) -(3x-1)(x-3)

(3x+1)(x+2)