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3x2 + 10x + 3 = (x + 3)(3x + 1).
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What is the factorization of this trinomial 3x2 plus 36x plus 81?
3x2 + 36x + 81 = 3(x2 + 13x + 27)
What is the factorization of the trinomial 3x2 plus 36x plus 81?
3x2 + 36x + 81 = 3(x2 + 12x + 27) = 3(x + 3)(x + 9), which are its prime factors; or, if you prefer, 3x2 + 36x + 81 = (3x + 9)(x + 9), which is also accurate. You may easily verify these results by multiplying back.
What is the factorization of x2 plus 10x plus 21?
x2 + 10x + 21 = (x + 3)(x + 7) You need to find 2 numbers which sum to 10 and whose product of 21. In this case 3 + 7 = 10 and 3 x 7 = 21.
Factor expression 3x2 plus 48x plus 192?
3x2 + 48 + 192 = 3x2 + 240 = 3 (x2+ 80)
How do you factor 3x squared plus 10x minus 8?
3x2 + 10x - 8The auxiliary equation is 3x2 + 10x - 24 [because 8*3 = 24] Two factors of -24 which sum to 10 are 12 and -2. So the factorisation of the auxillary is (3x + 12)*(3x - 2) = 3*(x + 4)*(3x - 2) Dividing by the 3 used to create the auxiliary gives the solution as (x + 4)*(3x - 2).
What is the complete factorization of 10x - 3 - 3x2?
-3x2+10x-3 -(3x2-10x+3) -(3x-1)(x-3)
How do you Factor 3X squared plus 10X plus 3?
3x2 + 10x + 3 = (x + 3)(3x + 1).
What is the factorization of this trinomial 3x2 plus 36x plus 81?
3x2 + 36x + 81 = 3(x2 + 13x + 27)
What is the factorization of the polynomial 3x2 plus 33x plus 54?
3x2 + 33x + 54 =3(x2 + 11x + 18) = 3(x + 9)(x + 2)
Determine whether each binomial is a factor of x3 plus 3x2-10x-24 of x plus 4?
X + 4 is a factor of x^3 + 3x^2 - 10x - 24 along with (x + 2) and (x - 3)
What is the factorization of the trinomial 3x2 plus 36x plus 81?
3x2 + 36x + 81 = 3(x2 + 12x + 27) = 3(x + 3)(x + 9), which are its prime factors; or, if you prefer, 3x2 + 36x + 81 = (3x + 9)(x + 9), which is also accurate. You may easily verify these results by multiplying back.
How do you factor out 5x plus 10x?
5x + 10x doesn't need factorization as you can just add them up (5x+10x=15x). However, if you really want to, 5x+10x=5x(1+2)=5x(3)=15x
What is the factorization of x2 plus 10x plus 21?
x2 + 10x + 21 = (x + 3)(x + 7) You need to find 2 numbers which sum to 10 and whose product of 21. In this case 3 + 7 = 10 and 3 x 7 = 21.
What is the rule for the prime factorization of six?
6 ^ 3 2 answer:3x2
Factor the trinomal -8x plus 3x2 - 3?
-8x + 3x2 - 3
How do you factor 3x squared plus 10x minus 8?
3x2 + 10x - 8The auxiliary equation is 3x2 + 10x - 24 [because 8*3 = 24] Two factors of -24 which sum to 10 are 12 and -2. So the factorisation of the auxillary is (3x + 12)*(3x - 2) = 3*(x + 4)*(3x - 2) Dividing by the 3 used to create the auxiliary gives the solution as (x + 4)*(3x - 2).
What is six plus ten x plus 3?
6 + 10x + 3 = 9 + 10x
