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-6-4i.
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∙ 11y ago
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What is the conjugate of 3 plus 4i?
When finding the conjugate of a binomial, you just reverse the sign. So the conjugate of 3+4i is 3-4i.
What is the additive inverse of 6 plus 4i?
The additive inverse of 6+4i is -6-4i since their sum is 0. It is analogous to real numbers where the additive inverse of 6 is -6 since 6+-6 =6-6=0 In the case of complex numbers, we add them by adding the real parts and then adding the imaginary parts. So to find the complex additive inverse of a+bi, we find the inverse of a which is -a and of bi which is -bi and so the additive inverse is -a-bi
What is the sum of 6 - 4i and 2 4i?
Add the real and the imaginary parts separately.
What is the product for 2 plus 4i?
A product is a binary operatoin. That is, it requires two numbers to be combined. There is only one number, 2 + 4i, in the question.
What two numbers multiply to 20 but add together to 4?
24
What is the conjugate of 3 plus 4i?
When finding the conjugate of a binomial, you just reverse the sign. So the conjugate of 3+4i is 3-4i.
What is the conjugate of -5 4i?
-9
What is the conjugate of the complex number 7-4i?
To get the conjugate simply reverse the sign of the complex part. Thus conj of 7-4i is 7+4i
What is conjugate of 4i open bracket -2 -3i close bracket?
4i(-2 -3i) = 4i×-2 - 4i×-3i = -8i -12i² = -8i + 12 = 12 -8i → the conjugate is 12 + 8i
What is the conjugate of 6 plus i?
The conjugate of 6 + i is 6 - i.
2 plus 4i - 7 plus 4i?
(2 + 4i) - (7 + 4i) = -5 2 + 4i - 7 + 4i = -5 + 8i
What is the sum of two complex conjugate number?
Since the imaginary parts cancel, and the real parts are the same, the sum is twice the real part of any of the numbers. For example, (5 + 4i) + (5 - 4i) = 5 + 5 + 4i - 4i = 10.
What is 2-4i over 4 plus 2i put in the form of a plus bi?
To solve this type of problem, multiply both the numerator and denominator by the conjugate of the denominator. (2 - 4i) / (4 + 2i) = (2 - 4i)(4 - 2i) / (4 + 2i)(4 - 2i) then expand all the terms, and simplify. = (8 - 20i + 8i2) / (16 - 4i2) = (8 - 20i - 8) / (16 + 4) = -20i / 20 = -i Which in the required answer format becomes, 0 + i.
What is the complex form of 4 plus 4i plus 4 plus 6i?
the problem: what is 4 + 4i + 4 + 6i what you do is add the real and imaginary parts, thus: 4+4 and 4i+6i = 8+10i answer.
How do you factor xsquared plus 16?
(x - 4i)(x + 4i) where i is the square root of -1
What is the additive inverse of 6 plus 4i?
The additive inverse of 6+4i is -6-4i since their sum is 0. It is analogous to real numbers where the additive inverse of 6 is -6 since 6+-6 =6-6=0 In the case of complex numbers, we add them by adding the real parts and then adding the imaginary parts. So to find the complex additive inverse of a+bi, we find the inverse of a which is -a and of bi which is -bi and so the additive inverse is -a-bi
What is multiplies to 20 but adds to 4?
24
