They are the complex conjugate numbers +/- 3*sqrt(2)*i where i is the imaginary square root of -1.
6+5i
8 - 8i
11 + 17i is an IMAGINARY number. . Its conjugate is 11 - 17i NB Note the change of sign only.
The product is a^2 + b^2.
-6-4i.
The conjugate is 7-5i
When finding the conjugate of a binomial, you just reverse the sign. So the conjugate of 3+4i is 3-4i.
The idea here is to change the sign before the imaginary term. In this case, since there is a minus, you change it to a plus.
The concept of conjugate is usually used in complex numbers. If your complex number is a + bi, then its conjugate is a - bi.
They are the complex conjugate numbers +/- 3*sqrt(2)*i where i is the imaginary square root of -1.
-2 - 3i
To find the complex conjugate change the sign of the imaginary part: For 11 + 5i the complex conjugate is 11 - 5i.
The conjugate base of NH4+ is NH3 (ammonia). A conjugate base is formed by the removal of a proton (H+) from the parent acid or cation.
8
6+2i
6+5i