It is 45
There is a set of four consecutive even integers whose sum is four. The set is: -2, 0, 2 and 4.
4 and 5
There is no possible answer. The sum of two consecutive even numbers MUST leave a remainder of 2 when divided by 4. That is, the sum must be divisible by 2 but must not be divisible by 4.
If n is the smallest of the four integers, their sum is 4n+6.
There aren't any. 340 is divisible by 4 while the sum of any two consecutive even numbers cannot be divisible by 4.There aren't any. 340 is divisible by 4 while the sum of any two consecutive even numbers cannot be divisible by 4.There aren't any. 340 is divisible by 4 while the sum of any two consecutive even numbers cannot be divisible by 4.There aren't any. 340 is divisible by 4 while the sum of any two consecutive even numbers cannot be divisible by 4.
The sum of any two consecutive integers is odd. Try it out. 3 + 4 = 7 4 + 5 = 9 If it works for those, it works for all of them.
-4 and -5
The numbers are -5 and -4.
There is no such combination.
The numbers are -4, -2, 0, and 2.
No two consecutive integers have a sum of 2012.
There is no pair of consecutive even integers whose sum is 264 - as their average is divisible by 4, that must mean that the sum of the unit digits of each of the pair of numbers could never be a multiple of 4 - which 264 is.