4 and 5
Wiki User
∙ 2012-10-17 00:56:54-2 + -3 + -4 = -9
There are no consecutive odd integers whose sum is equal to 35. 9+11+13 = 33, and 11+13+15 = 39.
-1, -3, -5
Let's talk this out and see if we can work it out. The sum of the first N odd integers means, 1+3+5+7+9+11+... Where N is how many odd numbers we're adding. Let's choose numbers for N, and see if we can find a pattern. N=1 --> 1 (sum of the first odd integer) N=2 --> 1 + 3 = 4 (sum of the first 2 odd integers) N=3 --> 1 + 3 + 5 = 9 (sum of the first 3 odd integers) N=4 --> 1 + 3 + 5 + 7 = 16 Do you notice a pattern yet? Take a look at when N = 2, what is the sum? That's right, 4! and when N = 3... the sum is 9. N = 4 the sum is 16.... I see a pattern, do you? Answer: If you don't, you'll notice that the sum of the first N odd integers is always = N2
-8 -9
The sum of even integers cannot end with 9. why not
-2 + -3 + -4 = -9
-4 and -5
7, 8, 9
Two consecutive integers whose sum is 19 is 10 & 9; 10+9 = 19.
36
They are 8+9 = 17
The sum of any two consecutive integers is odd. Try it out. 3 + 4 = 7 4 + 5 = 9 If it works for those, it works for all of them.
The integers are 7, 8 and 9.
7 + 9 + 11 = 27
72/3 = 24 and 7+8+9 = 24 so the integers are 7, 8 and 9.
The numbers are -5 and -4.