Q: What is the sum of 3 consecutive integers that -9?

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-2 + -3 + -4 = -9

There are no consecutive odd integers whose sum is equal to 35. 9+11+13 = 33, and 11+13+15 = 39.

-1, -3, -5

Let's talk this out and see if we can work it out. The sum of the first N odd integers means, 1+3+5+7+9+11+... Where N is how many odd numbers we're adding. Let's choose numbers for N, and see if we can find a pattern. N=1 --> 1 (sum of the first odd integer) N=2 --> 1 + 3 = 4 (sum of the first 2 odd integers) N=3 --> 1 + 3 + 5 = 9 (sum of the first 3 odd integers) N=4 --> 1 + 3 + 5 + 7 = 16 Do you notice a pattern yet? Take a look at when N = 2, what is the sum? That's right, 4! and when N = 3... the sum is 9. N = 4 the sum is 16.... I see a pattern, do you? Answer: If you don't, you'll notice that the sum of the first N odd integers is always = N2

The numbers are: 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 +02 = 2 +03 = 5+04 = 9+05 = 14+06 = 20+07 = 27+08 = 35+09 = 44+10 = 54+11 = 65 or 32 and 33

Related questions

The sum of even integers cannot end with 9. why not

-2 + -3 + -4 = -9

-4 and -5

7, 8, 9

Two consecutive integers whose sum is 19 is 10 & 9; 10+9 = 19.

36

The sum of any two consecutive integers is odd. Try it out. 3 + 4 = 7 4 + 5 = 9 If it works for those, it works for all of them.

They are 8+9 = 17

7 + 9 + 11 = 27

The integers are 7, 8 and 9.

72/3 = 24 and 7+8+9 = 24 so the integers are 7, 8 and 9.

7 + 9 + 11 = 27