Distance = root(3.8^2 + 3.9^2)
Distance = 5.4452 inches
x2 + 2x - 38 = 0 ∴ x2 + 2x + 1 = 39 ∴ (x + 1)2 = 39 ∴ x + 1 = ±√39 ∴ x = -1 ±√39
There are (40 x 39 x 38)/(3 x 2) = 9,880 of them
39!/34! x 5! = (39 x 38 x 37 x 36 x 35)/(5 x 4 x 3 x 2) = 575,757 of them
You can calculate that as (39 x 38 x 37 x 36 x 35 x 34) / (1 x 2 x 3 x 4 x 5 x 6).
It depends on which unit of measurement you are using.
39% of 38% is 14.82%.39 x .38 x100 = 14.82
x2 + 2x - 38 = 0 ∴ x2 + 2x + 1 = 39 ∴ (x + 1)2 = 39 ∴ x + 1 = ±√39 ∴ x = -1 ±√39
38" x 75"
There are (40 x 39 x 38)/(3 x 2) = 9,880 of them
39 x 38 x 37 x 36 x 35 =69090840
39!/34! x 5! = (39 x 38 x 37 x 36 x 35)/(5 x 4 x 3 x 2) = 575,757 of them
Just 37. 35 = 5 x 7 36 = 2 x 2 x 3 x 3 38 = 2 x 19 39 = 3 x 13
19 with 1 remaining 39 - 1 = 38 = 2 x 19
Let's call the two numbers x and x+1. Thenx(x+1) = 1482, sox2 + x -1482 = 0.Using the quadratic formula gives x = (-1 ± √(1-4(1)(-1482)) / 2 = -39 or 38.So, if both numbers are positive, then one is 38, and the next number is 39, so 38*39 = 1482.(If both numbers were negative, then -39*-38 would also work.)
39 and 1 13 and 3
39 - 1 = 38
1+38 = 39