What are two consecutive numbers with a product of 1482?

Answer 1

Let's call the two numbers x and x+1. Then

x(x+1) = 1482, so

x2 + x -1482 = 0.

Using the quadratic formula gives x = (-1 ± √(1-4(1)(-1482)) / 2 = -39 or 38.

So, if both numbers are positive, then one is 38, and the next number is 39, so 38*39 = 1482.

(If both numbers were negative, then -39*-38 would also work.)