Let's call the two numbers x and x+1. Then
x(x+1) = 1482, so
x2 + x -1482 = 0.
Using the quadratic formula gives x = (-1 ± √(1-4(1)(-1482)) / 2 = -39 or 38.
So, if both numbers are positive, then one is 38, and the next number is 39, so 38*39 = 1482.
(If both numbers were negative, then -39*-38 would also work.)
Two consecutive two digit numbers that when multiplied give the product of 812 are 28 and 29.
two consecutive numbers with the product of 1722 = 41 & 42
The numbers are 56 and 57.
The numbers are 42 and 43.
23x24.
They are: 38 times 39 = 1482
Find two consecutive numbers with the value of 4160
There are only two prime numbers that are consecutive numbers, 2 and 3. Their product is 2 x 3 = 6. The first prime numbers are 2, 3, 5, and 7 and the only two consecutive prime numbers whose product is a single digit are 2 and 3. (The next two consecutive prime numbers, 3 and 5, have a two-digit product.)
Two consecutive two digit numbers that when multiplied give the product of 812 are 28 and 29.
two consecutive numbers with the product of 1722 = 41 & 42
The numbers are 28 and 29.
The numbers are 56 and 57.
The numbers are 24 and 25.
The numbers are 43 and 44.
They are 14 and 15.
The numbers are 42 and 43.
The numbers are 14 and 15.