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Well I cant graph it for you but its a linear line

some points would be

(0,-1) (1,-2) (2,-3)(3,-4) (-1,0) (-2,1) (-3,2) and so on

Q: What is the correct graph for the equation y equals -x-1?

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y intercept is when x is zero then you solve. slope is rise over run or y -y1 divided by x -x1 you graph by puting the y intersept on the y axis then you take the slope and do the rise then the run

Select two values of x: (x1 and x2) within the domain. Solve the equation of the line to find the corresponding values for y: (y1 and y2). Then the gradient = (y1 - y2) / (x1 - x2)

Select two points on the graph and suppose their coordinates are (x1, y1) and (x2, y2) then the gradient = (y1 - y2) / (x1 - x2) provided that x1 and x2 are different. If not, the gradient is not defined.

Rise divided by run. (Y2 - Y1) / (X2 - X1) - with (X1, Y1) and (X2, Y2) being two points on the graph.

to calculate the area of any straight line graph or part of a graph, you need to select two points. for example (x1,y1) and (x2,y2). once you have selected the points you put then into the equation m=delta y/delta x (change in y divided by the change in x) which is easier as m=(y2-y1)/(x2-x1) and m = the gradient

Related questions

the absolute value of displacement which is delta equals x2-x1

The steepness of a graphed equation is called the slope. Slope can be found after choosing to points on the graph. After recording the coordinate points (x1,y1) snd (x2, y2), slope= y2-y1/x2-x1, or rise/run.

y intercept is when x is zero then you solve. slope is rise over run or y -y1 divided by x -x1 you graph by puting the y intersept on the y axis then you take the slope and do the rise then the run

Select two values of x: (x1 and x2) within the domain. Solve the equation of the line to find the corresponding values for y: (y1 and y2). Then the gradient = (y1 - y2) / (x1 - x2)

it equals x1 it equals x1

Select two points on the graph and suppose their coordinates are (x1, y1) and (x2, y2) then the gradient = (y1 - y2) / (x1 - x2) provided that x1 and x2 are different. If not, the gradient is not defined.

Rise divided by run. (Y2 - Y1) / (X2 - X1) - with (X1, Y1) and (X2, Y2) being two points on the graph.

to calculate the area of any straight line graph or part of a graph, you need to select two points. for example (x1,y1) and (x2,y2). once you have selected the points you put then into the equation m=delta y/delta x (change in y divided by the change in x) which is easier as m=(y2-y1)/(x2-x1) and m = the gradient

use the formula y-y1=m(x-x1)

It is linear. The highest power is 1 (x = x1, y = y1) so it is linear.

Select any tow values of x, say x1 and x2.Calculate y1 = 5*x1 - 12 and y2 = 5*x2 - 12. Mark the points (x1, y1) and (x2, y2). Join them with a straight line and extend in both directions.

you need 2 points on the line y2-y1 slope=----- x2-x1