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to calculate the area of any straight line graph or part of a graph, you need to select two points.

for example (x1,y1) and (x2,y2).

once you have selected the points you put then into the equation

m=delta y/delta x (change in y divided by the change in x)

which is easier as

m=(y2-y1)/(x2-x1)

and m = the gradient

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Q: How do you find the gradient of velocity time graph?
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Related questions

What is the gradient of a graph in a displacement time and velocity time graphs?

In a displacement-time graph, the gradient represents velocity. In a velocity-time graph, the gradient represents acceleration.


How can you find the instantaneous acceleration of an object whose curve on the velocity time graph is a straight line?

It is the gradient (slope) of the line.


How do you find instantaneous velocity from position time graph?

To find instantaneous velocity from a position-time graph, you calculate the slope of the tangent line at a specific point on the graph. The slope represents the rate of change of position at that instant, which is equivalent to the velocity at that particular moment.


How do you calculate deceleration on a velocity time graph?

Deceleration on a velocity-time graph is calculated by finding the slope of the line segment representing the decrease in velocity. The formula for deceleration is given by the change in velocity divided by the time taken for the velocity to change. It indicates how quickly the object is slowing down.


How do you make an acceleration time graph from the data of a velocity time graph?

To create an acceleration-time graph from a velocity-time graph, you need to find the slope of the velocity-time graph at each point. The slope represents the acceleration at that specific instant. Plot these acceleration values against time to get the acceleration-time graph.


How can you recognize acceleration on a graph?

On a position-time graph, acceleration can be recognized as a non-zero slope, indicating a change in velocity over time. On a velocity-time graph, acceleration is represented by a non-zero slope or a curved line. Additionally, in both cases, acceleration can be identified by a constant increase or decrease in velocity over time.


How do you find the time acquired by initial velocity in an acceleration -time graph?

To find the time taken to acquire a certain velocity in an acceleration-time graph, locate the point on the graph where the velocity reaches the desired value. Then, find the corresponding time on the horizontal axis at that point. This time value represents the time taken to acquire the initial velocity.


What is the difference between a velocity time graph and a position time graph?

Simply put, a velocity time graph is velocity (m/s) in the Y coordinate and time (s) in the X and a position time graph is distance (m) in the Y coordinate and time (s) in the X if you where to find the slope of a tangent on a distance time graph, it would give you the velocity whereas the slope on a velocity time graph would give you the acceleration.


How do you go from a position graph to a velocity graph?

To go from a position graph to a velocity graph, you can calculate the slope of the position graph at each point. The slope at any given point on a position vs. time graph represents the velocity at that specific time. Therefore, the velocity graph would be a plot of the slopes at each point on the position graph.


On a speed time graph what measures acceleration?

Acceleration on a speed-time graph is represented by the slope of the line. A steeper slope indicates a greater acceleration. If the slope is positive, it indicates acceleration; if it is negative, it indicates deceleration.


What is a velocity time graph in detail?

A velocity time graph is still a velocity time graph - no matter the degree of detail that you look at it.


What are the nature of the distance time graphs for uniform and non unifrm motion of an object?

A distance-time graph for an object moving at a constant velocity will be a straight line - the gradient of the line corresponds to the velocity. Non-uniform motion will cause the gradient of the line to change.