20/10 g/cm^3
=2 g/cm^3
density = mass divided by volume density = 20/10 = 2 g/cm3
Pyrite has a density of 4.8-5g/cm3 mass = density x volume = (4.8-5)g/cm3 x 10 cm3 = 48 to 50 grams.
density = mass/volume density = 5/10 = 0.5 grams per cubic centimeter
Since density = mass/volume, D = 25/10 = 2.5g/cm^3
density = mass ÷ volume = 30 g ÷ 10 cm3 = 3 g/cm3
Density is mass per unit volume. If 10 cm3 weighs 20g, the density is 2 g/cc.
density = mass divided by volume density = 20/10 = 2 g/cm3
Its is 10 cm³ hun
Density is independent of the amount of material in a sample. A sample of a homogeneous substance used to find the density can have any volume. If a cm3 of the substance weighs 8.1 grams, then 10 cm3 will weigh 81.0 grams.We might consider water in a glass or bottle as an example. A small sample will have a given weight (mass) because water has a given density. Ten times that sample volume will have ten times the mass of that volume of water. The density of water does not change if we examine water in a small glass and another sample of the same water in a gallon jug.
We need to calculate the volume of a metal from the density to be sure. Density of pure gold = 19.3  g·cm-3Density of pure lead = 11.34  g·cm-3The volume of 20 g of gold = mass/density = 20 [g] / 19.3  g·cm-3 = 1.036 cm3 The volume of 10 g of lead = mass/density = 10 [g] / 11.34  g·cm-3 = 0.882 cm3 Hence, the volume of 20 g of gold is slightly greater than that of 10 g of lead. =========================
Density = mass/volume = 22/10 = 2.2 grams per cm^3.
Volume of a substance is measured in cubic units and is given by dividing its mass by its volume. In this case it is not possible to find the density of the cork since 2.71cm2 is a measurement of an area.
The **density** of a substance is defined as its mass per unit volume. We can calculate the density using the formula: [ \text{Density} (\rho) = \frac{\text{Mass} (m)}{\text{Volume} (V)} ] Given that the sample has a volume of **50 cm³** and a mass of **135 g**, let's determine the density: [ \rho = \frac{135 , \text{g}}{50 , \text{cm³}} ] The calculated density is approximately **2.7 g/cm³**[^10^]. Now let's compare this value to known densities: **Gold**: Gold has a density of *19.3 g/cm³*⁷. The sample's density is significantly lower. **Pure Water**: The density of pure water is approximately **1 g/cm³** at 4.0°C (39.2°F) . The sample's density is higher than water. **Aluminum**: Aluminum has a density of *2.7 g/cm³*[^10^]. The sample's density matches that of aluminum. **Ocean Water**: Ocean water contains dissolved salts, which increase its density. Seawater density typically ranges from *1.02 g/cm³ to 1.03 g/cm³*. The sample's density is higher than seawater. Based on the calculated density, the sample is most likely **aluminum**.
Just divide to get the density, and compare. 20 / 10 = 2 g/cm3, 20/2 = 10 g/cm3, so the first is less dense.
Density is weight per volume. It does not change because the size of the specimen changed. The total weight will increase, but not the density.
Pyrite has a density of 4.8-5g/cm3 mass = density x volume = (4.8-5)g/cm3 x 10 cm3 = 48 to 50 grams.
Density is mass divided by volume - for example grams per cubic centimeter (or "cc").I will assume that you meant that the volume is 10 cubiccentimeters.Then you get (20 grams) divided by (10 cc) = 2 g/cc