The derivative of a linear function is always its gradient
In the function y = x-1, the gradient is 1 as 1 is the co-efficient of 1x.
The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.
the derivative of 1x would be 1 the derivative of x to the power of 1 would be 1. the derivative of x+1 would be 1 the derivative of x-1 would be 1 im not sure what you are asking, but however you put it, it's 1.
The derivative of xe is e. The derivative of xe is exe-1.
Derivative of 1/x 1/x = x-1 Take the derivative (-1)x(-1-1) = -x-2 = 1/x2
The derivative of ln x is 1/x The derivative of 2ln x is 2(1/x) = 2/x
The derivative of nlogn is equal to logn 1.
Derivative of x = 1, and since sqrt(x) = x^(1/2), derivative of x^(1/2) = (1/2)*(x^(-1/2))Add these two terms together and derivative = 1 + 1/(2*sqrt(x))
If y = 3x +- 1, the derivative with respect to x is y' = 3.
3
3
d/dx of lnx is 1/x Therefore the derivative is 1/(1+x)
The idea is to use the addition/subtraction property. In other words, take the derivative of 5x, take the derivative of 1, and subtract the results.