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What is the derivative of 1 divided by fx under the conditions that fx is differentiable and fx cannot be 0?
Wiki User
∙ 14y ago
Negative the derivative of f(x), divided by f(x) squared.
-f'(x) / f²(x)
Wiki User
∙ 14y ago
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Where is f(x) discontinuous but not differentiable Explain?
Wherever a function is differentiable, it must also be continuous. The opposite is not true, however. For example, the absolute value function, f(x) =|x|, is not differentiable at x=0 even though it is continuous everywhere.
Why absolute value of x is not differentiable at point 0?
The absolute value of x, |x|, is defined as |x| = x, x>=0; -x, x<0. If you derive this, then you will find that the derivative is 1 when x>=0, and -1 when x<0. But this means that the derivative as x approaches 0 from the left does not equal the derivative as x approaches 0 from the right, as -1=/=1. So the limit as x approaches 0 does not exist, and therefore the gradient does not exist at that point, and so |x| cannot be differentiated at x = 0.
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What is the derivative of 3x 4?
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "divided by", "equals".If the question is about 3x + 4 or 3x - 4, then the answer is 3.
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