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It might become easier if you split the problem in half. Since we know that d/dx[f(x)-g(x)] is the same as the derivative of d/dx[f(x)] - d/dx[g(x)], you can rewrite your problem as d/dx(e)- d/dx(2x). (it's common usage to write coefficients in from of variables, but that's just notation). The derivative of e is simply 0 (since e is a constant) and the derivative of 2x is 2.
so d/dx(e-2x)=0-2=-2
Wiki User
∙ 14y ago
Wiki User
∙ 14y agoIf you mean e^(x2), then
the derivative =2e^(x2)
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You want e to the power x2, right? The Wikipedia gives an answer, at http://en.wikipedia.org/wiki/List_of_integrals_of_exponential_functions. I won't copy it here, too much trouble; and I don't know how to draw equations here. This answer is quite complicated; it seems you basically use successive approximations to get the integral (antiderivative), instead of a simple expression as you might expect.
How do you take the derivative of a trig function?
Trig functions have their own special derivatives that you will have to memorize. For instance: the derivative of sinx is cosx. The derivative of cosx is -sinx The derivative of tanx is sec2x The derivative of cscx is -cscxcotx The derivative of secx is secxtanx The derivative of cotx is -csc2x
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