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(1/2)x = 2-x = exp (ln 2-x) = exp( -x ln 2). Since d/dx exp(x) = exp(x), we can use the chain rule to find that:

d/dx (1/2)x = -(ln 2) exp(-x ln 2).

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Q: What is the derivative of half to the power of x?

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The square root of x = x to the power of a half

The derivative is 2x based on the power rule. Multiply the power by the coefficient of x then drop the power by one.

The first derivative of e to the x power is e to the power of x.

The derivative of ex is ex

2x

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The square root of x = x to the power of a half

The derivative is 2x based on the power rule. Multiply the power by the coefficient of x then drop the power by one.

The first derivative of e to the x power is e to the power of x.

The derivative of ex is ex

2x is the first derivative of x2.

x^0 = 1 for all x. The derivative of 1 is always zero.

e^(-2x) * -2 The derivative of e^F(x) is e^F(x) times the derivative of F(x)

2x

the derivative of 1x would be 1 the derivative of x to the power of 1 would be 1. the derivative of x+1 would be 1 the derivative of x-1 would be 1 im not sure what you are asking, but however you put it, it's 1.

e^[ln(x^2)]=x^2, so your question is really, "What is the derivative of x^2," to which the answer is 2x.

Your expression simplifies to just x^2 {with the restriction that x > 0}. The derivative of x^2 is 2*x

1 divided by x to the third power equals x to the negative third. The derivative of x to the negative third is minus three x to the negative fourth.