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What else can I help you with?
What is the derivative of e to the power of 2lnx?
Your expression simplifies to just x^2 {with the restriction that x > 0}. The derivative of x^2 is 2*x
What is the derivative of e power negative x?
d/dx (e-x) = -e-x
What is the derivative of xex2?
It is (e^x)^2 * (2*x^2 + 1)
What is the derivative of e the the power ln x?
y = e^ln x using the fact that e to the ln x is just x, and the derivative of x is 1: y = x y' = 1
What is the derivitive of e?
2.71828183 ==So the derivative of a constant is zero.If you have e^x, the derivative is e^x.
How do you do derivative 27ex?
I assume you mean 27 times e to the power x. 1) You take out the constant out. So, the derivative is 27 times the derivative of (e to the power x).2) You use the rule for the exponential function.
What is the derivative of x to the power of e?
e^[ln(x^2)]=x^2, so your question is really, "What is the derivative of x^2," to which the answer is 2x.
What is the derivative of e to the power ln x squared?
e^[ln(x^2)]=x^2, so your question is really, "What is the derivative of x^2," to which the answer is 2x.
What is the first derivative of e raised to the power of x?
The first derivative of e to the x power is e to the power of x.
What is the derivative of e to the power of 2lnx?
Your expression simplifies to just x^2 {with the restriction that x > 0}. The derivative of x^2 is 2*x
What is the derivative of e to the power of x?
The derivative of ex is ex
What is the antiderivative of sqrtx plus 4ex minus sinx?
The anti-derivative of sqrt(x) : sqrt(x)=x^(1/2) The anti-derivative is x^(1/2+1) /(1/2+1) = (2/3) x^(3/2) The anti-derivative is 4e^x is 4 e^x ( I hope you meant e to the power x) The anti-derivative of -sin(x) is cos(x) Adding, the anti-derivative is (2/3) x^(3/2) + 4 e^x + cos(x) + C
What is the derivative of e power negative x?
d/dx (e-x) = -e-x
What is the derivative of xex2?
It is (e^x)^2 * (2*x^2 + 1)
What is the derivative of e the the power ln x?
y = e^ln x using the fact that e to the ln x is just x, and the derivative of x is 1: y = x y' = 1
What is the derivative of e of 2x?
The derivative of ( e^{2x} ) can be found using the chain rule. The derivative is ( 2e^{2x} ), where the factor of 2 comes from differentiating the exponent ( 2x ). Thus, ( \frac{d}{dx} e^{2x} = 2e^{2x} ).
Find its nth derivative e to the power x sq By 2 multiply cosx?
I suggest you calculate the first 2 or 3 derivatives, and see whether you can find a pattern.
