Your expression simplifies to just x^2 {with the restriction that x > 0}. The derivative of x^2 is 2*x
d/dx (e-x) = -e-x
It is (e^x)^2 * (2*x^2 + 1)
y = e^ln x using the fact that e to the ln x is just x, and the derivative of x is 1: y = x y' = 1
2.71828183 ==So the derivative of a constant is zero.If you have e^x, the derivative is e^x.
I assume you mean 27 times e to the power x. 1) You take out the constant out. So, the derivative is 27 times the derivative of (e to the power x).2) You use the rule for the exponential function.
e^[ln(x^2)]=x^2, so your question is really, "What is the derivative of x^2," to which the answer is 2x.
The first derivative of e to the x power is e to the power of x.
e^[ln(x^2)]=x^2, so your question is really, "What is the derivative of x^2," to which the answer is 2x.
Your expression simplifies to just x^2 {with the restriction that x > 0}. The derivative of x^2 is 2*x
The derivative of ex is ex
The anti-derivative of sqrt(x) : sqrt(x)=x^(1/2) The anti-derivative is x^(1/2+1) /(1/2+1) = (2/3) x^(3/2) The anti-derivative is 4e^x is 4 e^x ( I hope you meant e to the power x) The anti-derivative of -sin(x) is cos(x) Adding, the anti-derivative is (2/3) x^(3/2) + 4 e^x + cos(x) + C
d/dx (e-x) = -e-x
It is (e^x)^2 * (2*x^2 + 1)
y = e^ln x using the fact that e to the ln x is just x, and the derivative of x is 1: y = x y' = 1
I suggest you calculate the first 2 or 3 derivatives, and see whether you can find a pattern.
ee is a constant and so its derivative is 0.