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Your expression simplifies to just x^2 {with the restriction that x > 0}. The derivative of x^2 is 2*x
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What is the derivative of 2lnx?
The derivative of ln x is 1/x The derivative of 2ln x is 2(1/x) = 2/x
What is the derivative of e to the power of -2 times x?
e^(-2x) * -2 The derivative of e^F(x) is e^F(x) times the derivative of F(x)
What is the derivative of e power negative x?
d/dx (e-x) = -e-x
What is the derivative of e the the power ln x?
y = e^ln x using the fact that e to the ln x is just x, and the derivative of x is 1: y = x y' = 1
What is the derivitive of e?
2.71828183 ==So the derivative of a constant is zero.If you have e^x, the derivative is e^x.
What is e2lnx?
It is a physics that can be simplified. The simplified version is y = e^(2lnx) lny = ln(e^(2lnx)) lny = 2lnx * lne lny = 2lnx * 1 lny = ln(x^2) y = x^2 x ^ 2 = e^(2lnx).
What is the derivative of 2lnx?
The derivative of ln x is 1/x The derivative of 2ln x is 2(1/x) = 2/x
What is the first derivative of e raised to the power of x?
The first derivative of e to the x power is e to the power of x.
What is the derivative of e to the power of x?
The derivative of ex is ex
What is the derivative of e to the power of -2 times x?
e^(-2x) * -2 The derivative of e^F(x) is e^F(x) times the derivative of F(x)
How do you find the extreme values of x2lnx?
Taking the derivative: 2lnx+2, 2(lnx+1). Extrema occur at y'=0. 2(lnx+1)=0,lnx=-1 x=e^(-1)=1/e y=-2/e So the extrema occurs at (1/e,-2/e)
How do you do derivative 27ex?
I assume you mean 27 times e to the power x. 1) You take out the constant out. So, the derivative is 27 times the derivative of (e to the power x).2) You use the rule for the exponential function.
What is the derivative of e power negative x?
d/dx (e-x) = -e-x
What is the derivative of x to the power of e?
e^[ln(x^2)]=x^2, so your question is really, "What is the derivative of x^2," to which the answer is 2x.
What is the derivative of e to the power ln x squared?
e^[ln(x^2)]=x^2, so your question is really, "What is the derivative of x^2," to which the answer is 2x.
What is the derivative of e the the power ln x?
y = e^ln x using the fact that e to the ln x is just x, and the derivative of x is 1: y = x y' = 1
What is the derivative of 1-lnx divided by 2x?
-1
