The first derivative of e to the x power is e to the power of x.
e^[ln(x^2)]=x^2, so your question is really, "What is the derivative of x^2," to which the answer is 2x.
d/dx (ex + x3) = ex + 3x2
The derivative is 2x based on the power rule. Multiply the power by the coefficient of x then drop the power by one.
That's because powers that involve the power "e", and logarithms to the base "e", are simpler than other powers or logarithms. For example: the derivative of ex is ex, while a derivative with other bases is more complicated; while the derivative of the natural logarithm (ln x, or logex) is 1/x.
The first derivative of e to the x power is e to the power of x.
e^(-2x) * -2 The derivative of e^F(x) is e^F(x) times the derivative of F(x)
d/dx (e-x) = -e-x
e^[ln(x^2)]=x^2, so your question is really, "What is the derivative of x^2," to which the answer is 2x.
y = e^ln x using the fact that e to the ln x is just x, and the derivative of x is 1: y = x y' = 1
e^[ln(x^2)]=x^2, so your question is really, "What is the derivative of x^2," to which the answer is 2x.
I assume you mean 27 times e to the power x. 1) You take out the constant out. So, the derivative is 27 times the derivative of (e to the power x).2) You use the rule for the exponential function.
Your expression simplifies to just x^2 {with the restriction that x > 0}. The derivative of x^2 is 2*x
d/dx (ex + x3) = ex + 3x2
2.71828183 ==So the derivative of a constant is zero.If you have e^x, the derivative is e^x.
The derivative is 2x based on the power rule. Multiply the power by the coefficient of x then drop the power by one.
The anti-derivative of sqrt(x) : sqrt(x)=x^(1/2) The anti-derivative is x^(1/2+1) /(1/2+1) = (2/3) x^(3/2) The anti-derivative is 4e^x is 4 e^x ( I hope you meant e to the power x) The anti-derivative of -sin(x) is cos(x) Adding, the anti-derivative is (2/3) x^(3/2) + 4 e^x + cos(x) + C