Sqrt(282 + 402) = a whisker under 48 ft 10 in
To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem. For a rectangle measuring 16 feet by 38 feet, the diagonal (d) can be calculated as (d = \sqrt{(16^2 + 38^2)}). This results in (d = \sqrt{(256 + 1444)} = \sqrt{1700} \approx 41.23) feet. Therefore, the diagonal measurement is approximately 41.23 feet.
Using Pythagoras: 462+282 = 2900 and the square root of this is the diagonal which is about 53.852 feet rounded to 3 decimal places
To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem. For a rectangle with sides of 30 feet and 32 feet, the diagonal (d) can be calculated as (d = \sqrt{30^2 + 32^2}). This gives (d = \sqrt{900 + 1024} = \sqrt{1924}), which simplifies to approximately 43.9 feet.
To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem. The formula is ( d = \sqrt{l^2 + w^2} ), where ( l ) is the length and ( w ) is the width. For a rectangle that is 420 feet long and 75 feet wide, the diagonal is calculated as ( d = \sqrt{420^2 + 75^2} ), which equals approximately 425.6 feet.
The diagonal is 48.877 feet.
The diagonal is 45.61 feet.
46.648 ft
To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem. For a rectangle measuring 16 feet by 38 feet, the diagonal (d) can be calculated as (d = \sqrt{(16^2 + 38^2)}). This results in (d = \sqrt{(256 + 1444)} = \sqrt{1700} \approx 41.23) feet. Therefore, the diagonal measurement is approximately 41.23 feet.
Diagonal = 36.9 feet
Use Pythagoras' theorem:- 502+302 = 3400 and the square root of this is the length of the diagonal which is about 58.309 feet to 3 dp
Using Pythagoras: 462+282 = 2900 and the square root of this is the diagonal which is about 53.852 feet rounded to 3 decimal places
235 Feet
116.6 feet
36.8782 ft
14.42 feet.
25.6125 (rounded)
Using Pythagoras' theorem it works out as 20 times the square root of 5 which is about 44.721 feet to three decimal places.