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Sqrt(282 + 402) = a whisker under 48 ft 10 in

Q: What is the diagonal measurement of a rectangle measuring 28 feet by 40 feet?

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Using Pythagoras: 462+282 = 2900 and the square root of this is the diagonal which is about 53.852 feet rounded to 3 decimal places

The diagonal is 48.877 feet.

Using Pythagoras; theorem the diagonal of the rectangle is 5 times square root of 65 or about 40 feet

57.3062 ft

97.617 ft

Related questions

The diagonal is 45.61 feet.

46.648 ft

Use Pythagoras' theorem:- 502+302 = 3400 and the square root of this is the length of the diagonal which is about 58.309 feet to 3 dp

Diagonal = 36.9 feet

Using Pythagoras: 462+282 = 2900 and the square root of this is the diagonal which is about 53.852 feet rounded to 3 decimal places

235 Feet

116.6 feet

36.8782 ft

14.42 feet.

25.6125 (rounded)

Using Pythagoras' theorem it works out as 20 times the square root of 5 which is about 44.721 feet to three decimal places.

That would be 34 feet.