By Pythagoras, (Diagonal)2 = 362 + 562 = 1296 + 3136 = 4432 sq ft So diagonal = +sqrt(4432) = 66.75 ft
Assuming that the measurements refer to a rectangle, the diagonal would be sqrt(272 + 122) = sqrt(729 + 144) = sqrt(873) = 29.55 ft (to 2 dp)
18.9 feet
Using Pythagoras Theorem then the diagonal = √(242 + 242) = √1152 = 33.94 ft (2dp)
Sqrt(282 + 402) = a whisker under 48 ft 10 in
Around 17.8. I did this with cossin, but check the answer with a calculator
The diagonal measurement of an 8 ft square is: 11.31 feet.
diagonal = sqrt(4^2 + 4^2) = sqrt(16 + 16) = sqrt(32) = 5.6568
To find the diagonal measurement of a square, you can use the Pythagorean theorem, which states that the square of the hypotenuse (the diagonal) is equal to the sum of the squares of the other two sides. In this case, the diagonal measurement would be the square root of (7^2 + 8^2) = √(49 + 64) = √113. Therefore, the diagonal measurement of a 7 ft by 8 ft square is approximately 10.63 feet.
About 8.5 feet.
By Pythagoras, (Diagonal)2 = 362 + 562 = 1296 + 3136 = 4432 sq ft So diagonal = +sqrt(4432) = 66.75 ft
36.8782 ft
20 ft
(Diagonal)2 = (36)2 + (26)2 = 1,972Diagonal = sqrt(1,972) = 44.4072 (rounded)
46.648 ft
Assuming that the measurements refer to a rectangle, the diagonal would be sqrt(272 + 122) = sqrt(729 + 144) = sqrt(873) = 29.55 ft (to 2 dp)
18 ft Diagonal of a square is the square root of 2, times the side.