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What is the diagonal measurement of 16 FT x 38 FT?
To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem. For a rectangle measuring 16 feet by 38 feet, the diagonal (d) can be calculated as (d = \sqrt{(16^2 + 38^2)}). This results in (d = \sqrt{(256 + 1444)} = \sqrt{1700} \approx 41.23) feet. Therefore, the diagonal measurement is approximately 41.23 feet.
What is diagonal measurement of rectangle measuring 46feet by 28 feet?
Using Pythagoras: 462+282 = 2900 and the square root of this is the diagonal which is about 53.852 feet rounded to 3 decimal places
What is diagonal measurement of 30 foot by 32 foot rectangle?
To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem. For a rectangle with sides of 30 feet and 32 feet, the diagonal (d) can be calculated as (d = \sqrt{30^2 + 32^2}). This gives (d = \sqrt{900 + 1024} = \sqrt{1924}), which simplifies to approximately 43.9 feet.
What is the diagonal measurement for a rectangle 420 feet long and 75 feet wide?
To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem. The formula is ( d = \sqrt{l^2 + w^2} ), where ( l ) is the length and ( w ) is the width. For a rectangle that is 420 feet long and 75 feet wide, the diagonal is calculated as ( d = \sqrt{420^2 + 75^2} ), which equals approximately 425.6 feet.
What is the diagonal measurement of 80'X30'?
To find the diagonal measurement of a rectangle with dimensions 80 feet by 30 feet, you can use the Pythagorean theorem. The diagonal ( d ) is calculated as ( d = \sqrt{(80^2 + 30^2)} ). This results in ( d = \sqrt{(6400 + 900)} = \sqrt{7300} ), which is approximately 85.0 feet.
What is the diagonal measurement of a rectangle measuring 36 feet by 28 feet?
The diagonal is 45.61 feet.
What is the diagonal measurement of a rectangle measuring 24 feet by 40 feet?
46.648 ft
What is the diagonal measurement of 16 FT x 38 FT?
To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem. For a rectangle measuring 16 feet by 38 feet, the diagonal (d) can be calculated as (d = \sqrt{(16^2 + 38^2)}). This results in (d = \sqrt{(256 + 1444)} = \sqrt{1700} \approx 41.23) feet. Therefore, the diagonal measurement is approximately 41.23 feet.
What is the diagonal measurement of a rectangle that is 28 Feet X 24 Feet?
Diagonal = 36.9 feet
What is the diagonal measurement of a rectangle measuring 50 feet by 30 feet?
Use Pythagoras' theorem:- 502+302 = 3400 and the square root of this is the length of the diagonal which is about 58.309 feet to 3 dp
What is diagonal measurement of rectangle measuring 46feet by 28 feet?
Using Pythagoras: 462+282 = 2900 and the square root of this is the diagonal which is about 53.852 feet rounded to 3 decimal places
What is the diagonal measurement of a rectangle 150 feet by 180 feet?
235 Feet
What is the diagonal measurement of a 60 feet by 100 feet rectangle?
116.6 feet
What is the diagonal measurement of a rectangle that is 24 feet by 28 feet?
36.8782 ft
What is the diagonal measurement of a rectangle 12feet x 8feet?
14.42 feet.
What is the diagonal measurement of a rectangle that is sixteen feet x twenty feet?
25.6125 (rounded)
What is the diagonal measurement of a rectangle measuring 20 feet by 40 feet?
Using Pythagoras' theorem it works out as 20 times the square root of 5 which is about 44.721 feet to three decimal places.
