To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem. For a rectangle with sides of 30 feet and 32 feet, the diagonal (d) can be calculated as (d = \sqrt{30^2 + 32^2}). This gives (d = \sqrt{900 + 1024} = \sqrt{1924}), which simplifies to approximately 43.9 feet.
Assuming that the 40 and 30 refer to sides of a rectangle and not to any of the infinite number of other possible shapes, the answer is 50.
To find the diagonal measurement of a rectangle with dimensions 80 feet by 30 feet, you can use the Pythagorean theorem. The diagonal ( d ) is calculated as ( d = \sqrt{(80^2 + 30^2)} ). This results in ( d = \sqrt{(6400 + 900)} = \sqrt{7300} ), which is approximately 85.0 feet.
The diagonal of a rectangle with the length of 30 yd and the width of 30 yd is approximately 42.43 yd
A square with a 30-inch diagonal measurement has sides of 21.21 inches in length.
To find the diagonal of a rectangle with dimensions 15 and 30, you can use the Pythagorean theorem. The diagonal ( d ) is calculated as ( d = \sqrt{(15^2 + 30^2)} ). This results in ( d = \sqrt{(225 + 900)} = \sqrt{1125} ), which simplifies to ( d \approx 33.54 ). Thus, the diagonal of a 15x30 rectangle is approximately 33.54 units.
32.311
That would be 34 feet.
Since the rectangle has right angles, you can use Pythagoras' Theorem in this case.
Assuming that the 40 and 30 refer to sides of a rectangle and not to any of the infinite number of other possible shapes, the answer is 50.
To find the diagonal measurement of a rectangle with dimensions 80 feet by 30 feet, you can use the Pythagorean theorem. The diagonal ( d ) is calculated as ( d = \sqrt{(80^2 + 30^2)} ). This results in ( d = \sqrt{(6400 + 900)} = \sqrt{7300} ), which is approximately 85.0 feet.
The diagonal of a rectangle with the length of 30 yd and the width of 30 yd is approximately 42.43 yd
Use Pythagoras' theorem:- 502+302 = 3400 and the square root of this is the length of the diagonal which is about 58.309 feet to 3 dp
The diagonal is approximately 38.42 feet.
A square with a 30-inch diagonal measurement has sides of 21.21 inches in length.
To find the diagonal of a rectangle with dimensions 15 and 30, you can use the Pythagorean theorem. The diagonal ( d ) is calculated as ( d = \sqrt{(15^2 + 30^2)} ). This results in ( d = \sqrt{(225 + 900)} = \sqrt{1125} ), which simplifies to ( d \approx 33.54 ). Thus, the diagonal of a 15x30 rectangle is approximately 33.54 units.
The diagonal will be the hypotenuse of a right triangle with legs 30 and 34 feet So its length is the square root of (34^2+ 30^2 )
302+482=3204 squareroot(3204) Answer=56.60388679