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What is the diagonal of a rectangle 28 x 64 feet?

Updated: 8/18/2019
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13y ago

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The diagonal is 69.856 feet.

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13y ago
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Q: What is the diagonal of a rectangle 28 x 64 feet?
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What is the diagonal measurement of a 28 foot x 64 foot rectangle?

using pythagorous 282 + 642 = 4880 square root = 69.856997 69.856997


What is the length of a rectangle with 64 feet?

The answer will depend on what 64 feet represents and probably also what the breadth of the rectangle is.


The width of a rectangle is 6 feet and the diagonal is 10 feet. What is the area of the rectangle?

Based on a right triangle and the 3, 4, 5 setup, the length of the rectangle is 8 feet, making the area 6 x 8 = 48 square feet.*Compute the length using the formula a2 + b2 = c2(the diagonal is the hypotenuse of the right triangle)62 + b2 = 10236 + b2 = 100b2 = 64 and b = 8


A rectangle is 15ft by 8 ft what is the length of a diagonal of a rectangle?

(Diagonal)2 = (15)2 + (8)2 = (225) + (64) = 289Diagonal = sqrt(289) = 17


A rectangle is 15 feet wide and 8 feet wide what is the digonal?

The diagonal of a rectangle 15 feet by 8 feet is the square root of the sum of the squares of the two sides: sqrt (15 x 15) + (8 x 8) = sqrt 225 + 64 = sqrt 289 = 17


What is the perimeter of a rectangle that measures 32 feet by 64 feet?

(64*2) + (32*2)=192 feet


What is perimeter of a rectangle with a side of 8 and diagonal of 10?

To find the perimeter of a rectangle we need to know the length of its sides. P = 2L + 2W Let L = 8, and W = √(102 - 82) = √(100 - 64) = √36 = 6 (by the Pythagorean theorem, where the hypotenuse is the diagonal and legs are the sides of the rectangle). Thus, P = 2(8) + 2(6) = 16 + 12 = 28.


What is the length if the diagonal of a rectangle whose length in 12 inches and width 7 inches?

13 57/64 "


What is the area of a rectangle which measures 15 feet?

23535;(64


What is the length of the diagonal of a rectangle with adjacent sides measuring 3 cm and 8 cm?

32 + 82 = diagonal2 (9 + 64) = 8.544


How long is the diagonal of a rectangle with dimensions 6M by 8M?

a2 + b2 = c2. 62 + 82=c2. 36+64=c2. 100=c2. sqrt(100)=sqrt(c2). c=10. So the diagonal is 10 m. long.


The length of a rectangle is three times its width and the area of the rectangle is 192ft squared what is its perimeter?

Area = 8*24 =192 square feet Perimeter = 24+24+8+8 = 64 feet