The diagonal is 69.856 feet.
using pythagorous 282 + 642 = 4880 square root = 69.856997 69.856997
The answer will depend on what 64 feet represents and probably also what the breadth of the rectangle is.
Based on a right triangle and the 3, 4, 5 setup, the length of the rectangle is 8 feet, making the area 6 x 8 = 48 square feet.*Compute the length using the formula a2 + b2 = c2(the diagonal is the hypotenuse of the right triangle)62 + b2 = 10236 + b2 = 100b2 = 64 and b = 8
(Diagonal)2 = (15)2 + (8)2 = (225) + (64) = 289Diagonal = sqrt(289) = 17
The diagonal of a rectangle 15 feet by 8 feet is the square root of the sum of the squares of the two sides: sqrt (15 x 15) + (8 x 8) = sqrt 225 + 64 = sqrt 289 = 17
(64*2) + (32*2)=192 feet
To find the perimeter of a rectangle we need to know the length of its sides. P = 2L + 2W Let L = 8, and W = √(102 - 82) = √(100 - 64) = √36 = 6 (by the Pythagorean theorem, where the hypotenuse is the diagonal and legs are the sides of the rectangle). Thus, P = 2(8) + 2(6) = 16 + 12 = 28.
13 57/64 "
23535;(64
32 + 82 = diagonal2 (9 + 64) = 8.544
a2 + b2 = c2. 62 + 82=c2. 36+64=c2. 100=c2. sqrt(100)=sqrt(c2). c=10. So the diagonal is 10 m. long.
Area = 8*24 =192 square feet Perimeter = 24+24+8+8 = 64 feet