To find the perimeter of a rectangle we need to know the length of its sides.
P = 2L + 2W
Let L = 8, and W = √(102 - 82) = √(100 - 64) = √36 = 6 (by the Pythagorean theorem, where the hypotenuse is the diagonal and legs are the sides of the rectangle).
Thus,
P = 2(8) + 2(6) = 16 + 12 = 28.
By using Pythagoras it is: 6+8+6+8 = 28 inches
By Pythagoras, the other side is 24 inches long. So the perimeter is 2*(10+24) = 2*34 = 68 inches.
One rectangle that has a perimeter of 30 has a length of 5 and a width of 10.
if you have the length of one side - plus the perimeter... Divide the perimeter by 2, then subtract the known side - this leaves you with the unknown dimension. For example... Say you have a side length of 10, and a perimeter of 30. 30/2 = 15, subtract 10 from that - and you get the missing measurement of 5.
Yes. For instance, the rectangle measuring 1 by 10 has a perimeter of 22 and an area of 10, whereas the rectangle measuring 4 by 4 has a perimeter of 16 and an area of 16.
The diagonal is 10 feet. The one side is 8 feet and the other side is 6 feet (by Pythagoras 82 + 62 = 102)). The perimeter is thus 28 feet.
The perimeter would be 28 meters.
By using Pythagoras it is: 6+8+6+8 = 28 inches
By Pythagoras, the other side is 24 inches long. So the perimeter is 2*(10+24) = 2*34 = 68 inches.
10
This question has no unique answer. A (3 x 2) rectangle has a perimeter = 10, its area = 6 A (4 x 1) rectangle also has a perimeter = 10, but its area = 4 A (4.5 x 0.5) rectangle also has a perimeter = 10, but its area = 2.25. The greatest possible area for a rectangle with perimeter=10 occurs if the rectangle is a square, with all sides = 2.5. Then the area = 6.25. You can keep the same perimeter = 10 and make the area anything you want between zero and 6.25, by picking different lengths and widths, just as long as (length+width)=5.
What is a rectangle were the area is 10 and the perimeter
One rectangle that has a perimeter of 30 has a length of 5 and a width of 10.
if you have the length of one side - plus the perimeter... Divide the perimeter by 2, then subtract the known side - this leaves you with the unknown dimension. For example... Say you have a side length of 10, and a perimeter of 30. 30/2 = 15, subtract 10 from that - and you get the missing measurement of 5.
56 cm Perimeter of a rectangle is given by 2(length + breadth). So, perimeter of given rectangle = 2(18 + 10) = 56
Yes. For instance, the rectangle measuring 1 by 10 has a perimeter of 22 and an area of 10, whereas the rectangle measuring 4 by 4 has a perimeter of 16 and an area of 16.
10