Using Pythagoras: 462+282 = 2900 and the square root of this is the diagonal which is about 53.852 feet rounded to 3 decimal places
Sqrt(282 + 402) = a whisker under 48 ft 10 in
57.3062 ft
A Square 28 by 36 - surely that is a rectangle Use Pythagoras' theorem: 282+362 = 2080 and the square root of this number is 45.607017 or about 46 units
find the width of a rectangle if its area is 9/28 of a square foot
Diagonal = 36.9 feet
The diagonal is 45.61 feet.
36.8782 ft
Using Pythagoras: 462+282 = 2900 and the square root of this is the diagonal which is about 53.852 feet rounded to 3 decimal places
Sqrt(282 + 402) = a whisker under 48 ft 10 in
The diagonal is 69.856 feet.
57.3062 ft
A Square 28 by 36 - surely that is a rectangle Use Pythagoras' theorem: 282+362 = 2080 and the square root of this number is 45.607017 or about 46 units
The perimeter would be 28 meters.
find the width of a rectangle if its area is 9/28 of a square foot
By using Pythagoras it is: 6+8+6+8 = 28 inches
To find the perimeter of a rectangle we need to know the length of its sides. P = 2L + 2W Let L = 8, and W = √(102 - 82) = √(100 - 64) = √36 = 6 (by the Pythagorean theorem, where the hypotenuse is the diagonal and legs are the sides of the rectangle). Thus, P = 2(8) + 2(6) = 16 + 12 = 28.