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The distance between these two points is 8.6.
I found this by finding the difference between the two x values and the difference of the two y values. The difference between the x value was found like this: 4- (-3)= 7 and the difference between the y values was found the same way: 1-6=-5.
Now to find the length between the two points, you need to use Pythagorean theorem because a right angle triangle is created with the difference between the two x values and the difference between the two y values. Lets call the length between these two points r. The formula to find r would be r^2= x^2 + y^2.
r^2= (7)^2 + (-5)^2
r^2= 49 + 25
r^2= 74
r= square root of 74
r=8.6
You square root 74 because to get r by itself you have to square root r to get rid of the exponent.
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∙ 13y ago
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7.2111 (rounded)
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What is the distance between the following points. (1 -2) and (1 -5)?
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What is the distance between the points named by -3 1 and -7 1 on the coordinate plane?
If you mean points of (-3, 1) and (-7, 1) then using the distance formula it is 10 units
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1
What is the distance between points 1 2 and 4 -1?
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
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