The distance between the points of (4, 3) and (0, 3) is 4 units
Points: (-4, 5) and (3, 16) Distance: square root of 170 which is about 13
The distance between (3, 7) and (-3, -1) is sqrt{[(3 - (-3)]2 + [7 - (-1)]2} = sqrt{[3 + 3]2 + [7 + 1]2} =sqrt{[6]2 + [8]2} = sqrt{36 + 64} = sqrt{100} = 10 units.
If you mean endpoints (-1, -3) and (11, -8) then by using the distance formula the length between the points is 13 units
Points: (-1, 2) and (4, 3) Slope: 1/5
The distance between the points is two times the square root of 3.
7.2111 (rounded)
Points: (-4, 3) and (3, -1) Distance: (3--4)2+(-1-3)2 = 65 and the square root if this is the distance which is just over 8
Points: (1, -2) and (1, -5) Distance: 3 units by using the distance formula
If you mean points of (-3, 1) and (-7, 1) then using the distance formula it is 10 units
1
If you mean points of: (-5, 1) and (-2, 3) then the distance is about 3.61 rounded to two decimal places
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
If you mean points of (1, -2) and (-9, 3) then the distance is about 11 units using the distance formula
what is the distance between the points (-3, -3) and (6, -1)
(-3-5)2+(-1--1)2 = 64 and the square root of this is the distance which is 8
The distance between the points of (4, 3) and (0, 3) is 4 units