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What is the empirical formula of a compound which is 64.80 percent carbon 6.35 percent hydrogen and 28.83 percent sulfur?
C4h2s
What is the emperical formula for cubane and 92.26 percent carbon?
The empirical formula for cubane with 92.26% carbon is C8H8. This ratio of carbon and hydrogen atoms aligns with the molecular structure of cubane.
What is the empirical formula of the compound that is 75 carbon and 25 hydrogen?
The empirical formula of a compound is the simplest whole number ratio of the elements in the compound. In C75H25, the ratio of carbon to hydrogen is 75:25, which is equal to 3:1. Thus, the empirical formula is C3H.
What is the empirical formula of a hydrocarbon containing 85.7 percent carbon and 14.3 percent hydrogen?
The molar ratio of carbon to hydrogen can be simplified by dividing by the smallest percentage. In this case, the ratio of carbon to hydrogen is 6:14 which simplifies to 3:7. Therefore, the empirical formula of the hydrocarbon is C3H7.
What contain carbohydrate?
Empirical formula. CH2O Carbon, hydrogen and oxygen.
What is the percent composition of a compound with the empirical formula CO2?
The percent composition of a compound with the empirical formula CO2 is 27.3% carbon and 72.7% oxygen.
What is the empirical formula for a compound that is 43.6 percent and 56.4 percent oxygen?
The empirical formula for the compound that is 43.6% carbon and 56.4% oxygen is CO2. This is because the ratio of carbon to oxygen in carbon dioxide is 1:2.
What is the emprical formula for the compound that contains 20 percent hydrogen and 80 percent carbon?
The atomic mass of hydrogen is 1 and that of carbon is 12, to the nearest integer. Therefore, a compound that contains 20 percent hydrogen and 80 percent carbon contains atoms of carbon in the ratio of 20:(80/12) = 20:(20/3) = 20 X 3/20 = 3. The smallest whole number ratio corresponding to this is 1:3, which corresponds to an empirical formula of CH3. (However, since carbon normally has a valence of 4 in hydrocarbons, the actual formula is probably C2H6.)
What is the empirical formula of a substance that contains 0.117 of carbon 0.233 of hydrogen and 0.117 of oxygen?
The molar ratios of carbon, hydrogen, and oxygen atoms are 1:2:1, so the empirical formula is CH₂O.
Combustion analysis of toluene a common organic solvent gives 5.86 mg of CO2 and 1.37 mg of H2O If the compound contains only carbon and hydrogen what is its empirical formula?
To find the empirical formula, we first need to convert the mass of CO2 and H2O to moles. From the molar ratios in the products, we find the moles of carbon and hydrogen present. Then, we determine the ratio of carbon to hydrogen atoms, giving the empirical formula as C7H8.
Use the masses of carbon dioxide CO2 and water H2O to determine the empirical formula of the alkane component?
To determine the empirical formula of the alkane component, first calculate the moles of carbon and hydrogen in the CO2 and H2O respectively. Then find the ratio of moles of carbon to hydrogen. Finally, simplify the ratio to the smallest whole number to obtain the empirical formula of the alkane component.
What is the empirical formula of C4H6?
The empirical formula of organic compounds is the lowest whole number ratio of atoms contained in the substance, as defined in chemistry. The empirical formula gives the minimal ratio of the number of various atoms that exist. It's an empirical formula, if the formula is shortened, but not the exact number of atoms in the molecule, C4H6 is the chemical formula for butane. For every mole of carbon, there are two moles of hydrogen. The carbon-to-hydrogen ratio equals 2:3. C2H3 is the empirical formula for butane (C4H6). Hence, the correct answer is C2H3.
