C4h2s
The empirical formula for a molecule containing 46.8 percent si and 53.2 percent o is in the middle of the two. These added together and divided by two will net the average result.
The annual compound interest rate is 18 percent.
Use the "rule of 72"...simply put, using compound interest you take the number 72 and divide it by the interest rate. Thus, at 5% the time to double is 14.4 years. This formula can be used for calculating a "double" for any interest rate using the same mathematical procedure.
The formula for finding the percent is =The given number/Total number *100 Here the given number is 36 . The total number is 150 . Therefore Percent = 36/150*100=24%
To convert 'D' degrees into a percent slope, you could use the Excel formula:= 100 * TAN ( D / 57.296 )
The empirical formula of this compound would be MgO.
You should solve for an empirical formula when you are given the percent composition of elements in a compound or when you have the molar mass of the compound but not the molecular formula. The empirical formula provides the simplest whole-number ratio of atoms in a compound.
Chi a+
The percent composition of a compound with the empirical formula CO2 is 27.3% carbon and 72.7% oxygen.
CHI3
p2o5
C3h4o2
The empirical formula of the compound with 40% sulfur and 60% oxygen is SO3 (sulfur trioxide). The ratio of sulfur to oxygen in the compound is 1:3, which simplifies to SO3.
The empirical formula for the compound that is 43.6% carbon and 56.4% oxygen is CO2. This is because the ratio of carbon to oxygen in carbon dioxide is 1:2.
The empirical formula of the compound with 52.7% K and 47.3% Cl is KCl (potassium chloride). This is because the ratio of potassium to chlorine atoms in the compound is 1:1, leading to the simple formula KCl.
The empirical formula for this compound is CaSO4. This can be determined by converting the percentages to moles, finding the mole ratio, and simplifying the subscripts to the smallest whole number ratio.
The empirical formula for a compound containing 13% magnesium and 87% bromine is MgBr2. This is because the ratio of magnesium to bromine atoms in the compound is 1:2, which corresponds to the formula MgBr2.