(a+b)^2=a^2+b^2+2ab
it should read "the quanitity "a plus b" squared equals a squared plus b squared plus two a times b"
See related link below for a picture that shows it graphically.
a square plus 2ab plus b square
(A+B)2 = (A+B).(A+B) =A2+AB+BA+B2 =A2+2AB+ B2 So the Answer is A + B the whole square is equal to A square plus 2AB plus B square. Avinash.
let, equation is ax2+bx+c=0 so, its solution will be x= (-b-sqrt(b*b-4ac))/2a x= (-b+sqrt(b*b-4ac))/2a it is generalized equation for finding roots of Quadratic eq.
(a+b)cube = a cube + b cube + 3a square b + 3ab square
1.774225a
The roots are (if the equation is of the form Ax2 + Bx + C = 0 ((-B) + Square Root of (B2 - 4xAxC)) / 2xA and ((-B) - Square Root of (B2 - 4xAxC)) / 2xA
For example if the question was √36 + √25 and the other was√36 +25 but the square root line was across the whole equation would it change the answer? And what would be the answer for both of them?
A single equation such as the one in the question cannot be solved.
'a' minus 'b' whole cube is equal to 'a cube' minus 'b cube' minus (3 a square b ) plus (3 a b square) . .. .....thanks
You never square a whole equation. That's just silly.
The quadric equation is: negative b plus or minus the square root of b squared minus 4ac all over(divided by) 2a
(a-b)2 = a2 _ 2ab+b2