CH3-C=O-NH2 +HCl----> CH3-C=O-OH+ NH4Cl
Answer:12mL of 50% solution and 24mL of 20% solution must be mixed to produce 36mL of a 30% acid solutionLet x = 50% acid solutiony = 20% acid solution Equations:x + y = 36mL ----equation (1)0.5x + 0.2y = 0.3 * 360.5x + 0.2y = 10.8multiplying by 105x + 2y = 108 ----equation (2)eliminating equations (1) and (2)-2(x + y = 36)-2-2x -2y = -725x +2y = 108=========3x = 36x=12substitute x=12 to equation (1)12 + y = 36y = 36 - 12y = 24thus 12mL of 50% solution and 24mL of 20% solution must be mixed to produce 36mL of a 30% acid solution
Answer:170mL of 5% acid solution and 30mL of 25% solution must be mixed to produce 200mL of a 8% acid solutionLet x = 5% acid solutiony = 25% acid solution Equations:x + y = 200mL ----equation (1)0.05x + 0.25y = 0.08 * 2000.05x + 0.25y = 16multiplying by 1005x + 25y = 1600 ----equation (2)eliminating equations (1) and (2)-5(x + y = 200)-5-5x -5y = -10005x +25y = 1600=========20y = 600y=30substitute x=30 to equation (1)x + 30 = 200x = 200 - 30x = 170thus 170mL of 5% solution and 30mL of 25% solution must be mixed to produce 200mL of a 8% acid solution
Answer:525mL of 75% solution and 420mL of 30% solution must be mixed to produce 945mL of a 50% acid solutionLet x = 75% acid solutiony = 30% acid solution Equations:x + y = 945mL ----equation (1)0.75x + 0.3y = 0.5 * 9450.75x + 0.3y = 472.5multiplying by 10075x + 30y = 4725 ----equation (2)eliminating equations (1) and (2)-30(x + y = 945)-30-30x -30y = -2835075x +30y = 4725============45x = 23625x=525substitute x=525 to equation (1)525 + y = 945y = 945 - 525y = 420thus 525mL of 75% solution and 420mL of 30% solution must be mixed to produce 945mL of a 50% acid solution
Its an equation you can use to find the pH of a solution. it is.... --- pH = pKa + log (Base/Acid) --- these may help too Ka = 10^-pKa Kw = Ka*Kb
x = amount of acid to add. y = final volume. 5 gal + x = y original amount of acid + acid added = final amount of acid (5 X .2) + x = O.5y Subtract the second equation from the first one. 5 - 1 + x - x = y - 0.5y 4 = 0.5y 8 = y Therefore the final volume is 8 gallons. 5 gal + x = 8 x = 3 gal. the amount of pure acid to add. Check the answer 5 X .2 = 1 gal of acid in original solution. 3 gallons added = 4 gallons total acid in solution. 4 gallons total acid in final solution of 8 gallons total solution = 50% acid.
Acetamide has a chemical formula of C2H5NO, and sulphuric acid is H2SO4. Their reaction is C2H5NO + H2SO4 <--> C2H6NO + HSO4. Note however, that the conjugate acid of acetamide may take two forms due to the non bonding electrons on the oxygen and nitrogen atoms of acetamide.
Acidic hydrolysis: hydrolysis in an acid solution (pH under 7) Basic hydrolysis: hydrolysis in a basic solution (pH above 7)
HCl In solution. H + and Cl - An easy hydrolysis with this strong acid.
If using acid-catalyzed hydrolysis of starch you can tell the hydrolysis is complete with the solution no longer gives a bluish/purple color with iodine solution. The color should be colorless.
It is a base It is a base It is a base
If using acid-catalyzed hydrolysis of starch you can tell the hydrolysis is complete with the solution no longer gives a bluish/purple color with iodine solution. The color should be colorless.
An acetamide is an amide of acetic acid, chemical formula CH3CONH2.
write chemical equation for the reaction between viscose solution and sulphuric acid
write chemical equation for the reaction between viscose solution and sulphuric acid
There are three protolysis steps:H3PO4 ---> H+ + H2PO4-H2PO4- ---> H+ + HPO42-HPO42- ---> H+ + PO43-
Acid hydrolysis using sulphuric acid and water (equilibrium reaction). The ester splits into a carboxylic acid and alcohol, protons donated from the acid. The solution can then be distilled and the remaining acid can be checked using UV indicator. Acid hydrolysis using sulphuric acid and water (equilibrium reaction). The ester splits into a carboxylic acid and alcohol, protons donated from the acid. The solution can then be distilled and the remaining acid can be checked using UV indicator.
Hydrolysis is a process of breaking the bonds in a water molecule into their component gases, hydrogen and oxygen. Hydrolysis is not an acid.