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What is the equation of a line with gradient -3 that goes through the origin?
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What is a linear function that goes through the origin?
it is just that- a linear function that goes through ther origin. ======================================================= Any equation y = ax, where a is a constant, will do so.
How do you graph the linear equation x equals y?
the slope is 1, and goes through the origin. It's a straight, diagonal line.
How can you find the unit rate on a graph that goes through the origin?
It is the gradient of the straight line joining the origin to any point on the graph. Thus, if A = (p,q) is any point on the graph, the average unit rate between the origin and A is q/p (provided p is non-zero).
Write the equation of the line that goes through the point 0 -4 with slope m equals -2?
The standard form for a straight line equation is y = mx + c, where 'm' is the gradient (slope) and 'c' is the y intercept when 'x' is zero. The equation for the line with details as shown in the question is y = -2x - 4
How do you name the equation of a line that is perpendicular to y equals 1 half x-3 and goes through the point x equals 0 and y equals 3?
L1: y = 1/2*x - 3Gradient of the line = 1/2Negative reciprocal of gradient = -1/(1/2) = -2That is, gradient of perpendicular = -2.This line goes through (0,3),(y - 3) = 2*(x - 0)y - 3 = 2xy = 2x + 3L1: y = 1/2*x - 3Gradient of the line = 1/2Negative reciprocal of gradient = -1/(1/2) = -2That is, gradient of perpendicular = -2.This line goes through (0,3),(y - 3) = 2*(x - 0)y - 3 = 2xy = 2x + 3L1: y = 1/2*x - 3Gradient of the line = 1/2Negative reciprocal of gradient = -1/(1/2) = -2That is, gradient of perpendicular = -2.This line goes through (0,3),(y - 3) = 2*(x - 0)y - 3 = 2xy = 2x + 3L1: y = 1/2*x - 3Gradient of the line = 1/2Negative reciprocal of gradient = -1/(1/2) = -2That is, gradient of perpendicular = -2.This line goes through (0,3),(y - 3) = 2*(x - 0)y - 3 = 2xy = 2x + 3
What is a linear function that goes through the origin?
it is just that- a linear function that goes through ther origin. ======================================================= Any equation y = ax, where a is a constant, will do so.
The equation y equals ax describes the graph of a line If the value of a is positive the line?
goes through the origin, up and to the right
How do you graph the linear equation x equals y?
the slope is 1, and goes through the origin. It's a straight, diagonal line.
How can you find the unit rate on a graph that goes through the origin?
It is the gradient of the straight line joining the origin to any point on the graph. Thus, if A = (p,q) is any point on the graph, the average unit rate between the origin and A is q/p (provided p is non-zero).
How does one find out if an equation's graph goes through the origin?
-- Take the equation -- Set either 'x' or 'y' equal to zero -- Solve the resulting equation for the remaining variable -- If the remaining variable is then also zero, then the origin is on the graph of the function If the graph is a straight line ('x' and 'y' appear in the equation only to the 1st power), then the equation has to be in the form of a simple ratio ... like (y = Kx) or (x = Ky) or (xy = K) or (x/y = K) ... in order to go through the origin.
How do you find an equation to a line that is parallel to y-3 and passes through the point (26)?
The gradient of the line y = -3 is 0. So any parallel line has the equation y = c.Since it goes though the point (2, 6), c = 6 and so the equation is y = 6.
Write the equation of the line that goes through the point 0 -4 with slope m equals -2?
The standard form for a straight line equation is y = mx + c, where 'm' is the gradient (slope) and 'c' is the y intercept when 'x' is zero. The equation for the line with details as shown in the question is y = -2x - 4
How do you name the equation of a line that is perpendicular to y equals 1 half x-3 and goes through the point x equals 0 and y equals 3?
L1: y = 1/2*x - 3Gradient of the line = 1/2Negative reciprocal of gradient = -1/(1/2) = -2That is, gradient of perpendicular = -2.This line goes through (0,3),(y - 3) = 2*(x - 0)y - 3 = 2xy = 2x + 3L1: y = 1/2*x - 3Gradient of the line = 1/2Negative reciprocal of gradient = -1/(1/2) = -2That is, gradient of perpendicular = -2.This line goes through (0,3),(y - 3) = 2*(x - 0)y - 3 = 2xy = 2x + 3L1: y = 1/2*x - 3Gradient of the line = 1/2Negative reciprocal of gradient = -1/(1/2) = -2That is, gradient of perpendicular = -2.This line goes through (0,3),(y - 3) = 2*(x - 0)y - 3 = 2xy = 2x + 3L1: y = 1/2*x - 3Gradient of the line = 1/2Negative reciprocal of gradient = -1/(1/2) = -2That is, gradient of perpendicular = -2.This line goes through (0,3),(y - 3) = 2*(x - 0)y - 3 = 2xy = 2x + 3
What does a positive and a negative gradient look like?
A positive gradient goes uphill from left to right A negative gradient goes downhill from left to right
Does the force vs acceleration graph goes through origin?
No
What is the which formula can be used in finding the equation of a line if a point and slope is given?
y=mx + c c is where the line goes thrugh the y axis find gradient (m) by rise over run. for example if the line goes up 2 every time it goes across 1 the gradient is 2/1 which is just 2. get it?
What is it called when a graph goes straight though the origin?
A root of the equation that defines the line graphed exists at 0.
