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-- Take the equation
-- Set either 'x' or 'y' equal to zero
-- Solve the resulting equation for the remaining variable
-- If the remaining variable is then also zero, then the origin is on the graph of the function
If the graph is a straight line ('x' and 'y' appear in the equation only to the 1st power), then the equation has to be in the form of a simple ratio ... like (y = Kx) or (x = Ky) or (xy = K) or (x/y = K) ... in order to go through the origin.
What else can I help you with?
How do you use a graphing calculator to solve quadratic equations?
Graph the equation then find the x intercepts.
What is the graph of a quadratic formula?
In general, quadratic equations have graphs that are parabolas. The quadratic formula tells us how to find the roots of a quadratic equations. If those roots are real, they are the x intercepts of the parabola.
What are the steps for writing the equation of a function from a graph?
1. Decide if the graph looks like any standard type of graph you've seen before. Is it a type of sine or cosine? A quadratic? A circle or ellipse? A line? An exponential? (You get the idea.) If you can't find a standard type to match your desired graph, pick one that looks close to it and recognize that you will be doing an approximation to your function.2. Once you have an idea of what you're graph should be like, think about the equations that are used to describe that graph. Where do the numbers go and how do they affect how the graph looks/moves/ behaves? Some functions, such as circles, hyperbolas, and quadratics, have standard equations with variables based on the important features of the graph (such as the center, maximums or minimums).3. Find the important and/or interesting parts of the graph and use them in the equation. As stated before, ellipses and such have special equations to describe them. Sines and cosines require the amplitude, frequency, and phase shift.4. Check your equation if you can. It's always good to plug a few of the points that are in your graph to make sure your equation is accurate. It's especially good to try out points you did NOT use to find your equation. If it works for these, then you probably did it right.
Find the intercepts for the graph of the equation given x plus 5y equals 0?
x + 5y = 0Subtract 5y from each side of the equation, just to put 'x' and 'y' on opposite sides.x = -5yThis is interesting. If EITHER 'x' OR 'y' is zero, then the other one is also zero.The only place on the graph where that is true is the origin. So the line goes through the origin,and the 'x' and 'y' intercepts are both zero.
Which graph could be used to find the solution of the system of equations y equals 2x plus 6 and y equals x2 plus 4x plus 3?
One way would be to graph the two equations: the parabola y = x² + 4x + 3, and the straight line y = 2x + 6. The two points where the straight line intersects the parabola are the solutions. The 2 solution points are (1,8) and (-3,0)
How do you find if a graph is proportional?
It is a straight line through the origin, with a positive slope.It is a straight line through the origin, with a positive slope.It is a straight line through the origin, with a positive slope.It is a straight line through the origin, with a positive slope.
How can you find the unit rate on a graph that goes through the origin?
It is the gradient of the straight line joining the origin to any point on the graph. Thus, if A = (p,q) is any point on the graph, the average unit rate between the origin and A is q/p (provided p is non-zero).
How do you find parametric equations to represent the graph of a given rectangle equation?
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How do you solve systems of equations by graphing?
-- Graph each equation individually. -- Examine the graph to find points where the individual graphs intersect. -- The points where the individual graphs intersect are the solutions of the system of equations.
How do you use a graphing calculator to solve quadratic equations?
Graph the equation then find the x intercepts.
What are graphing method?
graphing method is when you graph two lines and then find the intersection which is the answer of the system of equations
How can you find the unit rate on a gragh that goes through the origin?
Divide the ordinate (y-coord) of any point on the graph by its abscissa (x-coord).
How do you find the solution set of pair linear equations?
By the substitution method By the elimination method By plotting them on a graph
How do you solve a system of equations by graphing?
Write each equations in popular form. ... Make the coefficients of one variable opposites. ... Add the equations ensuing from Step two to remove one variable. Solve for the last variable. Substitute the answer from Step four into one of the unique equations.
How you can obtain the solution to a system of equations by graphing?
In the same coordinate space, i.e. on the same set of axes: -- Graph the first equation. -- Graph the second equation. -- Graph the third equation. . . -- Rinse and repeat for each equation in the system. -- Visually examine the graphs to find the points (2-dimension graph) or lines (3-dimension graph) where all of the individual graphs intersect. Since those points or lines lie on the graph of each individual graph, they are the solution to the entire system of equations.
What is the graph of a quadratic formula?
In general, quadratic equations have graphs that are parabolas. The quadratic formula tells us how to find the roots of a quadratic equations. If those roots are real, they are the x intercepts of the parabola.
How can you find a unit rate on a graph that goes through origin?
To find a unit rate on a graph that goes through the origin, identify the coordinates of a point on the line (other than the origin). The unit rate is determined by calculating the slope of the line, which is the change in the y-value divided by the change in the x-value (rise over run). Since the line passes through the origin, the slope directly represents the unit rate of change between the two quantities. For example, if the point is (4, 8), the unit rate would be 8/4 = 2, indicating that for every 1 unit increase in x, y increases by 2 units.
