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L1: y = 1/2*x - 3

Gradient of the line = 1/2

Negative reciprocal of gradient = -1/(1/2) = -2

That is, gradient of perpendicular = -2.

This line goes through (0,3),

(y - 3) = 2*(x - 0)

y - 3 = 2x

y = 2x + 3

L1: y = 1/2*x - 3

Gradient of the line = 1/2

Negative reciprocal of gradient = -1/(1/2) = -2

That is, gradient of perpendicular = -2.

This line goes through (0,3),

(y - 3) = 2*(x - 0)

y - 3 = 2x

y = 2x + 3

L1: y = 1/2*x - 3

Gradient of the line = 1/2

Negative reciprocal of gradient = -1/(1/2) = -2

That is, gradient of perpendicular = -2.

This line goes through (0,3),

(y - 3) = 2*(x - 0)

y - 3 = 2x

y = 2x + 3

L1: y = 1/2*x - 3

Gradient of the line = 1/2

Negative reciprocal of gradient = -1/(1/2) = -2

That is, gradient of perpendicular = -2.

This line goes through (0,3),

(y - 3) = 2*(x - 0)

y - 3 = 2x

y = 2x + 3

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11y ago

L1: y = 1/2*x - 3

Gradient of the line = 1/2

Negative reciprocal of gradient = -1/(1/2) = -2

That is, gradient of perpendicular = -2.

This line goes through (0,3),

(y - 3) = 2*(x - 0)

y - 3 = 2x

y = 2x + 3

This answer is:
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Q: How do you name the equation of a line that is perpendicular to y equals 1 half x-3 and goes through the point x equals 0 and y equals 3?
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