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How do you name the equation of a line that is perpendicular to y equals 1 half x-3 and goes through the point x equals 0 and y equals 3?
Wiki User
∙ 11y ago
L1: y = 1/2*x - 3
Gradient of the line = 1/2
Negative reciprocal of gradient = -1/(1/2) = -2
That is, gradient of perpendicular = -2.
This line goes through (0,3),
(y - 3) = 2*(x - 0)
y - 3 = 2x
y = 2x + 3
L1: y = 1/2*x - 3
Gradient of the line = 1/2
Negative reciprocal of gradient = -1/(1/2) = -2
That is, gradient of perpendicular = -2.
This line goes through (0,3),
(y - 3) = 2*(x - 0)
y - 3 = 2x
y = 2x + 3
L1: y = 1/2*x - 3
Gradient of the line = 1/2
Negative reciprocal of gradient = -1/(1/2) = -2
That is, gradient of perpendicular = -2.
This line goes through (0,3),
(y - 3) = 2*(x - 0)
y - 3 = 2x
y = 2x + 3
L1: y = 1/2*x - 3
Gradient of the line = 1/2
Negative reciprocal of gradient = -1/(1/2) = -2
That is, gradient of perpendicular = -2.
This line goes through (0,3),
(y - 3) = 2*(x - 0)
y - 3 = 2x
y = 2x + 3
Wiki User
∙ 11y ago
Wiki User
∙ 11y agoL1: y = 1/2*x - 3
Gradient of the line = 1/2
Negative reciprocal of gradient = -1/(1/2) = -2
That is, gradient of perpendicular = -2.
This line goes through (0,3),
(y - 3) = 2*(x - 0)
y - 3 = 2x
y = 2x + 3
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What would be an equation for the line that passes through the point -14 and is perpendicular to y equals 13x plus 4?
If -14 is the y intercept then it is: y = -1/13x -14
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Known equation: 5x-2y = 3 or y = 5/2x -3/2 Slope of known equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y- -4 = -2/5(x-3) => 5y =-2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0
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If -14 is the y intercept then it is: y = -1/13x -14
What is the equation passing through the point 3 -4 which is perpendicular to the line 5x -2y equals 3?
Known equation: 5x-2y = 3 or y = 5/2x -3/2 Slope of known equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y- -4 = -2/5(x-3) => 5y =-2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0
What is the perpendicular distance from the point 4 -2 to the straight line of 2x -y -5 equals 0?
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What is the equation of a line that is perpendicular to and passes through the point (4 6)?
That would depend on its slope which has not been given.
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