If you mean points of: (2, -8) and (0, 0) then the slope is -4 and equation is y = -4x
Points: (9, 1) and (4, 16) Slope: -3 Equation: y = -3x+28
Points: (-2.5, -0.5) and (4.5, -1) Slope: -1/14 Equation: y = -1/14x-19/28 in slope intercept form
Points: (9, 1) and (4, 16) Slope: (1-16)/(9-4) = -3 Equation: y-1 = -3(x-9) => y = -3x+28 Equation: y-16 = -3(x-4) => y = -3x+28
Points: (9, 1) and (4, 16) Slope: (1-16)/(9-4) = -3 Equation: y-1 = -3(x-9) => y = -3x+28 Equation: y-16 = -3(x-4) => y = -3x+28
y = -1/14x-19/28 which can be expressed in the form of 2x+28y+19 = 0
If you mean points of (-2, 8) and (4, -4) then the slope is -2 and the straight line equation works out as y = -2x+4
It is an algebraic expression but if you mean 5x-4y-28 = 0 then it is a straight line equation.
You've basically asked "what is 8 choose 2?", which is 8! / ( 6! * 2! ) or 28. The two are identical because each pair of points determines a line (since no three points are collinear). Since there are 28 ways to choose 2 items from a set of 8 items, there are 28 possible pairs of points and therefore 28 lines.
x+7y+4 = 0 => y = -1/7x-4/7 The slope of the second equation is the reciprocal of the first equation with the minus sign changing to a plus sign. y = mx+c where m is the slope and c is the intercept on the y axis So: 7*4+c = 0 28+c = 0 c = -28 Therefore the perpendicular equation is: y = 7x-28 which can be expressed in the form of 7x-y-28 = 0
8 collinear points determine 28 unique line segments
0:28 + 1:00 + 6:00 = 7:28 Answer: 7 hours 28 minutes
Using: y2-y1 over x2-x1 the slope is -1/14 Using: y = mx+c the equation is y = -1/14x-19/28 which can be expressed in the form of 2x+28y+19 = 0