-2
1 and 3
y = x2 + 12x + 21At the max or min point, the first derivative of the function = 0.2x + 12 = 02x = -12x = -6
(-3, -5)
y = - 4x - 4
6y
17
-2
1 and 3
y = x2 + 12x + 21At the max or min point, the first derivative of the function = 0.2x + 12 = 02x = -12x = -6
(-3, -5)
y = - 4x - 4
No solution. Multiply second equation by 3 and get 12x + 6y = 0 but already stated 12x + 6y = 9...
12x - 9y = 6, 12x + 20y = 64 29y = 58 y = 2 x = 2
The equation is in standard form y = mx + b where m is the slope and b is the y-intercept. For y = 12x + 1, m = 12 so the slope is 12.
Y = 62
It is a straight line equation with a slope of 14 and a y intercept of -5