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Q: What is the equation of a with a center 4 and 2 and radius 9?

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I think it is center: (-4, 3) ; radius: 2 Apex:)

center 5,-3 radius 4

x² + y² = 4.

It is (x - 7)^2 + (y - 4)^2 = 4

It is: (x-1)^2 +(y+4)^2 = 4

It is: (x-4)^2+(y+5)^2 = 4^2

(x-2)2+(y-4)2=36

(x+2)2 + (y-4)2 = 36

(x+4)2 + (y-2)2 = 9 it is a circle

It is: (x+2)^2 +(y+4)^2 = 36

It is x2 + y2 = 4

The equation is: (x+3)^2 +(y+5)^2 = 16

If you mean a circle center at (3, 1) and a radius of 2 then the equation of the circle is (x-3)^2 +(y-1)^2 = 4

(x + 4)2 + (y + 3)2 = 49 is.

(x + 4)2 + (y - 7)2 = 62

(x - 8)2 + (y - 4)2 = 49

( x+4 )^2 +( y-7)^2=36

It is: (x-8)^2 + (y-4)^2 = 49

x2 + y2 = 2

The equation of a circle with center (h, k) = (-2, -4), and a radius r = 6 is(x - h)2 + (y - k)2 = r2(x - -2)2 + (y - -4)2 = 62(x + 2)2 + (y + 4)2 = 36

It is (x + 7)2 + (y + 2)2 = 42

It is: (x-2)^2 +(y-7)^2 = 16

It is: (x+3)^2 + (y-5)^2 = 16

Centre of the circle: (3, 8) Radius of the circle: 2 Cartesian equation of the circle: (x-3)^2 + (y-8)^2 = 4

If you mean: (x+5)^2 + (y+3)^2 = 16 Then its center is at (-5, -3) and its radius is 4