(x+4)2 + (y-2)2 = 9
it is a circle
(x+2)2 + (y-4)2 = 36
(x-2)2+(y-4)2=36
The equation of a circle with center (h, k) = (-2, -4), and a radius r = 6 is(x - h)2 + (y - k)2 = r2(x - -2)2 + (y - -4)2 = 62(x + 2)2 + (y + 4)2 = 36
Centre of the circle: (3, 8) Radius of the circle: 2 Cartesian equation of the circle: (x-3)^2 + (y-8)^2 = 4
The general formula: (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center and r is the radius. So the required equation of the circle is: (x - -4)^2 + (y - 0)^2 = 10^2 (x + 4)^2 + y ^2 = 100
387
I think it is center: (-4, 3) ; radius: 2 Apex:)
center 5,-3 radius 4
x² + y² = 4.
It is (x - 7)^2 + (y - 4)^2 = 4
It is: (x-4)^2+(y+5)^2 = 4^2
(x+2)2 + (y-4)2 = 36
It is: (x+2)^2 +(y+4)^2 = 36
(x-2)2+(y-4)2=36
It is x2 + y2 = 4
The equation is: (x+3)^2 +(y+5)^2 = 16
If you mean a circle center at (3, 1) and a radius of 2 then the equation of the circle is (x-3)^2 +(y-1)^2 = 4