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(x-2)2+(y-4)2=36

Q: What is the equation for a circle with a center of 2 4 and a radius of 6?

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The equation of circle is (x−h)^2+(y−k)^2 = r^2, where h,k is the center of circle and r is the radius of circle. so, according to question center is origin and radius is 10, therefore, equation of circle is x^2 + y^2 = 100

The equation of the circle is: x^2 + y^2 = 81

Centre of the circle: (3, 8) Radius of the circle: 2 Cartesian equation of the circle: (x-3)^2 + (y-8)^2 = 4

Equation of circle: (x-2)^2 +(y+9)^2 = 49

(x + 2)2 + (y - 2)2 = 1

Related questions

Equation of any circle, with any radius, and its center at any point: [ x - (x-coordinate of the center) ]2 + [ y - (y-coordinate of the center) ]2 = (radius of the circle)2

The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2

The equation of circle is (x−h)^2+(y−k)^2 = r^2, where h,k is the center of circle and r is the radius of circle. so, according to question center is origin and radius is 10, therefore, equation of circle is x^2 + y^2 = 100

depends on the equation.

Center of circle: (6, 8) Radius of circle: 3

The equation of the circle is: x^2 + y^2 = 81

Centre of the circle: (3, 8) Radius of the circle: 2 Cartesian equation of the circle: (x-3)^2 + (y-8)^2 = 4

Equation of circle: (x-2)^2 +(y+9)^2 = 49

If you mean a circle center at (3, 1) and a radius of 2 then the equation of the circle is (x-3)^2 +(y-1)^2 = 4

The equation of the circle is: (x+3.2)^2 +(y+2.1)^2 = 18.49

center 5,-3 radius 4

x² + y² = 4.