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Perpendicular slope: -1/4 Perpendicular equation: y-0 = -1/4(x-3) => y = -0.25x+3
2-3
Yes, I could, if I knew the slope of the line given.
The x-coordinate of any point on the y-axis is 0. The y-axis is a line perpendicular to the x-axis. Any point on a line perpendicular to the x-axis has the same x-coordinate. The y-axis is the line perpendicular to the x-axis through 0, and has the equation x = 0; similarly, the x-axis is the line perpendicular to the y-axis through 0 and has the equation y = 0.
Perpendicular slope: 1/2 Perpnedicular equation: y-5 = 1/2(x-2) => y = 0.5x+4
That would depend on its slope which has not been given.
Perpendicular slope: -1/4 Perpendicular equation: y-0 = -1/4(x-3) => y = -0.25x+3
General formula
If a line has equation y = mx + c, the perpendicular line has gradient -1/m A line perpendicular to 3x + y = 2 has equation 3y = x + c; the value for c will be determined by a point through which the line must pass.
That depends on the equation that it is perpendicular too which has not been given but both equations will meet each other at right angles.
2-3
The perpendicular postulate states that if there is a line, as well as a point that is not on the line, then there is exactly one line through the point that is perpendicular to the given line.
Yes, I could, if I knew the slope of the line given.
The x-coordinate of any point on the y-axis is 0. The y-axis is a line perpendicular to the x-axis. Any point on a line perpendicular to the x-axis has the same x-coordinate. The y-axis is the line perpendicular to the x-axis through 0, and has the equation x = 0; similarly, the x-axis is the line perpendicular to the y-axis through 0 and has the equation y = 0.
If you mean: y=3x-4 and the point (2, 1) then the perpendicular equation is 3y=-x+5
Perpendicular slope: 1/2 Perpnedicular equation: y-5 = 1/2(x-2) => y = 0.5x+4
If you mean point (-1, 4) and equation of 4x-3y = -9 then y = 4/3x+3 Slope of equation: 4/3 Perpendicular slope: -3/4 Perpendicular equation: y-4 = -3/4(x--1) => 4y = -3x+13