That would depend on its slope which has not been given.
That depends on the equation that it is perpendicular too which has not been given but both equations will meet each other at right angles.
If you mean y = 3x+8 then the perpendicular slope will be -1/3 and the equation works out as 3y = -x+9
If you mean point (-1, 4) and equation of 4x-3y = -9 then y = 4/3x+3 Slope of equation: 4/3 Perpendicular slope: -3/4 Perpendicular equation: y-4 = -3/4(x--1) => 4y = -3x+13
If you mean line of 3x+2y = 5 then y = -3/2x+2.5 Perpendicular slope: 2/3 Perpendicular equation: 3y = 2x+18 or as 2x-3y+18 = 0
The line "x = 6" will be perpendicular to any line "y = C", where C is any constant. That means that the line which is perpendicular to "x=6" and passes through [-4, 5] will be "y = 5"
2-3
That depends on the equation that it is perpendicular too which has not been given but both equations will meet each other at right angles.
Perpendicular slope: -1/4 Perpendicular equation: y-0 = -1/4(x-3) => y = -0.25x+3
General formula
Perpendicular lines passing through a point are at right angles to each other.
If you mean y = 3x+8 then the perpendicular slope will be -1/3 and the equation works out as 3y = -x+9
Perpendicular slope: 1/2 Perpnedicular equation: y-5 = 1/2(x-2) => y = 0.5x+4
Yes, I could, if I knew the slope of the line given.
If you mean point (-1, 4) and equation of 4x-3y = -9 then y = 4/3x+3 Slope of equation: 4/3 Perpendicular slope: -3/4 Perpendicular equation: y-4 = -3/4(x--1) => 4y = -3x+13
Slope of line: 3 Perpendicular slope: -1/3 Equation: y-2 = -1/3(x-0) => y = -1/3x+2
Slope: -2 Equation: y--1 = -2(x-3) => y = -2x+5
If -14 is the y intercept then it is: y = -1/13x -14