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Slope=8

point=(-7,3)

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Q: What is the equation of the line that passes through the following points in point slope form. (-23)(2-3)?

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Answer this question…y = 2x + 6

The equation for the given points is y = x+4 in slope intercept form

If you mean points of (2, -2) and (-4, 22) then the equation is y = -4x+6

It is y = 2.

Points: (-1, 2) and (5, 2) Slope: 0 Equation: y = 2

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Answer this question…y = 2x + 6

Write the equation of the line that passes through the points (3, -5) and (-4, -5)

If you mean points of (2, -2) and (-4, 22) then the equation is y = -4x+6

The equation for the given points is y = x+4 in slope intercept form

Y= -3x + 8

It is y = 2.

Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.

In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.

Points: (0. 5) and (2, 3) Slope: -1 Equation: y = -x+5

If you mean points of (-4, 2) and (4, -2) Then the straight line equation works out as 2y = -x

If the points are (1,5) and (0,0) y = 5x

Points: (12, 8) and (17, 16) Slope: 8/5 Equation: 5y = 8x-32