(s, 2s) and (3s, 8s); s ≠ 0, otherwise we have just one point, the origin.
First, find the slope of the non-vertical line joining the two given points.
(2s - 8s)/(s - 3s) = -6s/-2s = 3
The slope of the perpendicular line must be the negative reciprocal of 3. Therefore it is -1/3.
Since the line is a perpendicular bisector, it must passes through the midpoint[(s +3s)/2, (2s + 8s)/2] = (2s, 5s).
Since we know the slope and one point on the line, we can write the point-slope form of the equation,
y - 5s = -(1/3)(x - 2s).
If you want, you can turn the equation into the slope-intercept form or the standard form.
Another Answer:-
It is: x+3y-17s = 0 in its general form
y = -2x+16 which can be expressed in the form of 2x+y-16 = 0
In its general form of a straight line equation the perpendicular bisector equation works out as:- x-3y+76 = 0
Their values work out as: a = -2 and b = 4
Endpoints: (s, 2s) and (3s, 8s) Midpoint: (2s, 5s) Slope of line: 3/1 Slope of perpendicular line: -1/3 Perpendicular bisector equation: y-5s = -1/3(x-2s) => 3y = -x+17s Perpendicular bisector equation in its general form: x+3y-17s = 0
The perpendicular bisector of the line joining the two points.
Given a straight line joining the points A and B, the perpendicular bisector is a straight line that passes through the mid-point of AB and is perpendicular to AB.
A perpendicular line is one that is at right angle to another - usually to a horizontal line. A perpendicular bisector is a line which is perpendicular to the line segment joining two identified points and which divides that segment in two.
Midpoint = (3+7)/2, (5+7)/2 = (5, 6) Slope of line segment = 7-5 divided by 7-3 = 2/4 = 1/2 Slope of the perpendicular = -2 Equation of the perpendicular bisector: y-y1 = m(x-x1) y-6 =-2(x-5) y = -2x+10+6 Equation of the perpendicular bisector is: y = -2x+16
Points: (-1, -6) and (5, -8) Midpoint: (2, -7) Perpendicular slope: 3 Perpendicular bisector equation: y = 3x -13
y = -2x+16 which can be expressed in the form of 2x+y-16 = 0
A perpendicular bisector is a line that divides a given line segment into halves, and is perpendicular to the line segment. An angle bisector is a line that bisects a given angle.
In its general form of a straight line equation the perpendicular bisector equation works out as:- x-3y+76 = 0
The perpendicular bisector of the straight line joining the two points.
Their values work out as: a = -2 and b = 4
Endpoints: (s, 2s) and (3s, 8s) Midpoint: (2s, 5s) Slope of line: 3/1 Slope of perpendicular line: -1/3 Perpendicular bisector equation: y-5s = -1/3(x-2s) => 3y = -x+17s Perpendicular bisector equation in its general form: x+3y-17s = 0
The perpendicular bisector of a line segment AB is the straight line perpendicular to AB through the midpoint of AB.
The perpendicular bisector of the line joining the two points.