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Q: What is the equation perpendicular to the line y equals - 8 x plus 6?

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negative 1

It is: 1/5

- 1/3

It is -1/2

y = 1/3x+4

The second equation works out as y = -1/2x+6 therefore it is perpendicular

In its general form of a straight line equation the perpendicular bisector equation works out as:- x-3y+76 = 0

For the line 2x + y = 8 , the slope equals ( -2 ) so the required slope of the line which is perpendicular to it is equal to (+1/2 )

It will be the positive reciprocal of -2 which is 1/2

the slope will be positive 1.5x the whole equation is y=4.5+1.5x

If a line has equation y = mx + c, the perpendicular line has gradient -1/m A line perpendicular to 3x + y = 2 has equation 3y = x + c; the value for c will be determined by a point through which the line must pass.

3x+y = 4 y = -3x+4 Perpendicular slope: 1/3

Equation of line: y = x+5 Equation of circle: x^2 +4x +y^2 -18y +59 = 0 The line intersects the circle at: (-1, 4) and (3, 8) Midpoint of line (1, 6) Slope of line: 1 Perpendicular slope: -1 Perpendicular bisector equation: y-6 = -1(x-1) => y = -x+7 Perpendicular bisector equation in its general form: x+y-7 = 0

4y= -3x + 12 y = -3/4x + 3 The perpendicular slope is 4/3

y equals -1/3x plus 4/3

7x-y-28 = 0

No because the slope of the second equation is 1/4 and for it to be perpendicular to the first equation it should be 1/3

If you mean: y = 6x+2 then its perpendicular line is -1/6.

The slope of the perpendicular is -(1/2) .

It could be y = -x+5

x - 4y = 3 is the slope of a line perpendicular to line whose equation is y -5 3x plus 8 3.

6

No, the two lines are not perpendicular.

10 is.

5