If: y = x^2 -10x +13 and y = x^2 -4x +7
Then: x^2 -10x +13 = x^2 -4x +7
Transposing terms: -6x +6 = 0 => -6x = -6 => x = 1
Substituting the value of x into the original equations point of contact is at: (1, 4)
Combine the equations together and using the quadratic equation formula it works out that the point of contact is at (5/8, 5/2)
5.477225575 squared equals 30.
The number that equals 121 when squared is 11.
b = sqrt32 or 4 root 2
No, it equals -2xy. lrn2math
If y = 2x +10 and y^2 = 10x then by forming a single quadratic equation and solving it the point of contact is made at (5/8, 5/2)
Combine the equations together and using the quadratic equation formula it works out that the point of contact is at (5/8, 5/2)
-2
-2
It is (-0.3, 0.1)
5.477225575 squared equals 30.
The number that equals 121 when squared is 11.
0
b = sqrt32 or 4 root 2
No, it equals -2xy. lrn2math
It works out that line 3x-y = 5 makes contact with the curve 2x^2 +y^2 = 129 at (52/11, 101/11) and (-2, -11)
4