If: 2x+y = 5 and x2-y2 = 3 Then the solutions work out as: (2, 1) and ( 14/3, -13/3)
If: y = 4x2-2x-1 and y = -2x2+3x+5 Then the length of the line works out as: 65/18 or 3.6111 ... recurring decimal 1
If you mean: (2x-7y)(x+y) then it is 2x squared -5xy -7y squared
Need signs between terms.
If the line y = 2x+1.25 is a tangent to the curve y^2 = 10x then it works out that when x = 5/8 then y = 5/2
2x squared plus 2x plus xy plus y or 2x(x+1) + y(x+1) or (x+1)(2x+y)
They intersect at the point of: (-3/2, 11/4)
It works out that line 3x-y = 5 makes contact with the curve 2x^2 +y^2 = 129 at (52/11, 101/11) and (-2, -11)