3t + 9 = 3(t + 3)
(2t + 1)(3t + 11)
(3t + 1)(t + 5)
3t - 15 = -9 3t - 15 (+15) = -9 (+15) 3t = 6 3t (/3) = 6 (/3) t = 2
4(t + 3)(t2 - 3t + 9)
The expression (3t \times 3t) can be simplified by multiplying the coefficients and the variable separately. First, multiply the coefficients: (3 \times 3 = 9). Then, multiply the variable (t) by itself: (t \times t = t^2). Therefore, the result is (9t^2).
(t - 3)(t^2 + 3t + 9)
-5
6t2-13t-63 = (3t+7)(2t-9) when factored.
Okay, I am going to assume you have a basic knowledge of Algebra and just show you how to solve the problem, step by step.6t2 + 13t - 63(3t - 7)(2t + 9)Check:(3t)(2t) - (7)(2t) + (3t)(9) - (7)(9)6t2 - 14t + 27t - 636t2 + 13t - 63
3t = the number 3 times the number t. If you need a better answer, post more information.
It is (3t-2)(3t+2) when factored and it is the difference of two squares
t(ht + 3)