(2t + 1)(3t + 11)
3t+11 = 29 3t = 29-11 3t = 18 t = 6
3t in lb.
-(t(3t + 1)(t - 8))
5-3t = 0.77 -3t = 0.77-5 -3t = -4.23 t = 1.41
3t + 9 = 3(t + 3)
It is (3t-2)(3t+2) when factored and it is the difference of two squares
3
The GCF is t.
If that's + 7t, the answer is (3t + 5)(2t - 1) If that's - 7t, the answer is (3t - 5)(2t + 1)
3st + 6tu = 3t (s + 2u)
3(t - 2)(t + 1)
6t2 - 7t - 5 = (3t - 5)*(2t + 1) So (6t2 - 7t - 5)/(3t - 5) = 2t + 1 provided that t is not 5/3
(2t + 1)(3t + 11)
4(t + 3)(t2 - 3t + 9)
6t - 5t - 6 = (3t + 2)(2t - 3)
(t - 3)(t^2 + 3t + 9)