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I am lazy, so I use the discriminant and the quadratic equation to solve these instead of factoring.

b^2 -4ac

(-2)^2 -4(3)(-2)

= 28 bigger than 1 and two real roots

X = -b +/- sqrt(b^2-4ac)/2a

X = -(-2) +/- sqrt[(-2)^2 - 4(3)(-2)]/2(3)

X = [2 +/- sqrt(28)]/6

this is exact, less factoring, but approximately........

X = 1.215

X = -0.5486

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13y ago
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Q: What is the factor of 3x2-2x-2 equals 0?
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