you set it equal to zero
7x^2 + 7x - 14 = 0
since there is a common factor of 7, you can divide each term by that, including the zero on the other side, which just gives you zero again...
(x^2 + x - 2) = 0
You have to find two numbers that multiply to give you the coefficent of the third term (c = -2), and add to give you the coefficient of middle term (b = 1)
so, +2, and -1 add to give you +1 (b), and multiply to give you -2 (c).
so the factors are:
x+2 and x-1
(and therefor the roots are x= -2, and x =1, but you just asked for the factors)
A factor of a perfect square trinomial is eithera number that is a factor of each term of the trinomial,a binomial that is a factor of the trinomial, ora product of the above two.For example, consider 4x2 + 8x + 4It has the factors2 or 4,(x + 1) or2x+2 = 2*(x+1) or 4x+4 = 4*(x+1)
the 5 kinds of factoring are common monomial factor, difference of two cubes, quadratic trinomial, perfect square trinomial,and difference of two square.
A trinomial is perfect square if it can be factored into the form
(x + 3)(x + 3)
(p - 9)(p - 9)
A perfect trinomial must be of the form a2x2 ± 2abxy + b2y2 and this factorises to (ax ± by)2.
5x2+11x+2 = (5x+1)(x+2) when factored
No.
If you want to know how to square a trinomial, you should first know the basic. (a+b+c)^2=? you have to square the first three terms then multiply 2 to the last three terms. All you have to do is to remember that a square of trinomial has 6 terms in the answer
It can be factored as the SQUARE OF A BINOMIAL
Factors are (7y - 3)(7y - 2) so it's not a perfect square.
If a trinomial is a perfect square, then the discriminant will equal 0. The discriminant is equal to B^2-4AC. The variables come from the standard form of a quadratic which is Ax^2+Bx+C In this problem, A=81, B=-72, and C=16 so the discriminant is: (-72)^2-4(81)(16)=5,184-5,184=0 so this is a perfect square trinomial. To factor, notice that 81=9^2 and 16=4^2, so 81x^2=(9x)^2. We can then factor the trinomial into (9x+4)(9x-4)